Use the References to access important values if needed for A student ran the following reaction in the laboratory at 330 K: CH4 (9)+CCl4 (9) = 2CH₂Cl₂ (9) When she introduced 0.0438 moles of CH4 (g) and 0.0602 moles of CCL4 (g) into a 1.00 liter container, she found the equilibrium concentration of CCl4 (g) to be 0.0544 M. Calculate the equilibrium constant, Ke, she obtained for this reaction. Kc = Submit Answer Retry Entire Group 9 more group attempts remaining

Chemistry for Engineering Students
4th Edition
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.34PAE: 1’he reaction in Exercise 12.33 was repeated. This time, the reaction began when only NO was...
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A student ran the following reaction in the laboratory at 330 K:
[Review Topics]
[References]
Use the References to access important values if needed for
CH4 (9) + CCl4 (g) = 2CH₂Cl₂ (g)
When she introduced 0.0438 moles of
CH4 (g) and 0.0602 moles of
CCL4 (g) into a 1.00 liter container, she found the equilibrium concentration of
CCl4 (g) to be 0.0544 M.
Calculate the equilibrium constant, Kc, she obtained for this reaction.
Kc =
Submit Answer
Retry Entire Group 9 more group attempts remaining
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Transcribed Image Text:20 A student ran the following reaction in the laboratory at 330 K: [Review Topics] [References] Use the References to access important values if needed for CH4 (9) + CCl4 (g) = 2CH₂Cl₂ (g) When she introduced 0.0438 moles of CH4 (g) and 0.0602 moles of CCL4 (g) into a 1.00 liter container, she found the equilibrium concentration of CCl4 (g) to be 0.0544 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = Submit Answer Retry Entire Group 9 more group attempts remaining Show Hint Cengage Learning | Cengage Technical Support MacBook Air
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