Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll, n equals 943 and x equals 509who said​ "yes." Use a 90%confidence level. a) Find the best point estimate of the population proportion p. b) Identify the value of the margin of error E. c) Construct the confidence interval.  d) Write a statement that correctly interprets the confidence interval.

Q: Della wants to make a one-sample z interval to estimate what proportion of her community members…

A: Consider the provided question, Della wants to make a one-sample z interval to estimate what…

Q: 2. Given: n=80, a = 15, level of confidence is 92%. What is the margin of error of the given data?

A:

Q: Use the confidence interval to find the margin of error and the sample mean. (1.52,2.06)

A: Given: Confidence interval is (1.52, 2.06) To determine: The margin error and The sample mean.…

Q: Use the confidence interval to find the margin of error and the sample mean. (1.71, 1.99)

A: Solution:  Given data: confidence Interval = (1.71, 1.99) To find: 1.Margin of error 2. Sample mean…

Q: How large a sample should be surveyed to estimate the true proportion of college students who surf…

A:

Q: Find the margin of error E that corresponds to the given statistics and confidence level.…

A: From the provided information, Confidence level = 98% Sample size (n) = 900 Success (p̂) = 0.40

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given that : n = 1072 x = 537 (a) to find the best point estimate of the population proportion p. P^…

Q: n a survey conducted by the Gallup organization September 6-9, 2012, 1,017 adults were were asked…

A: The proportion of respondents have a fair amount of confidence in the media is required. Let's…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.578,0.740)

A: Suppose the confidence interval is given as : (a,b) (x-MOE , x+MOE) = (0.578 , 0.740) Then to obtain…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In poll,…

A:

Q: If n=16, x(x-bar)=43, and s=9, find the margin of error at a 99% confidence level Give your answer…

A: The random variable X follows normal distribution. The sample size is 16. The sample mean is 43. The…

Q: Construct a 99% confidence interval estimate for the population mean, N = 36, ?̅= 135, σ = 24

A: As the population standard deviation σ is not known, we will use z-distribution.  The value of z at…

Q: (a) What percent of the scores are less than 19? (b) Out of 1500 randomly selected scores, about how…

A: mu = 19.9 s = 5.1

Q: An inspector took a random sample of 150 restaurants in Seattle and found that 30% in the sample…

A: a) Consider that p is the true population proportion of restaurants, which have food safety…

Q: According to The Census Bureau, 60% of adults buy clothing online. a) How many adults did they…

A: Solution: a. From the given information, p=0.60 and E=0.03. The confidence level is 0.95.

Q: Use the confidence interval to find the margin of error and the sample mean. (.228, 0.390)

A: We know that the Margin of error = (upper_limit - lower_imit )/2 and Sample mean = (upper limit +…

Q: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level E=

A: If n = 590 and ˆp=0.48, find the margin of error at a 99% confidence level

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given information: x=586 n=1006

Q: Find the value of t within a) 60% confidence level and n 17 %3D b) 75% confidence level and n = 8 c)…

A: We have given that,  (a) 60% confidence interval and n= 17 (b) 75% confidence interval and n = 8 (c)…

Q: A magazine provided results from a poll of 1500 adults who were asked to identify their favorite…

A: From the data given:   The value of p^ is the sample proportion   The value of q^ is found from…

Q: A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.…

A: GivenA poll of 500 adults asked to identify .among them 11% choose chocololate pie and the margin of…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: According to the given information, we have Confidence interval = (0.690, 0.718)

Q: Use the given degree of confidence and sample data to find margin of error for the population…

A: Solution: From the given information, X=123 and n=280.

Q: If n=23, ¯x (x-bar)=38, and s=5, find the margin of error at a 99% confidence level

A: The degrees of freedom is obtained as follows:

Q: If n=23, ¯x(x-bar)=34, and s=8, find the margin of error at a 99% confidence level Give your answer…

A: Solution: From the given information, n=23, x-bar=34 and s=8. The confidence level is 0.99.

Q: A school survey asked 20 questions about student characteristics and interests. State whether each…

A: Note:- Many a times, type of data would depend on the specific application as to how the data is…

Q: In 2010, a survey was given to 822 teenagers, aged 13 to 17, randomly selected by the allup Poll.…

A: Solution: Given information: n= 822 Sample size p^=0.84 Sample proportionq^= 1-p^=0.16 Assume level…

Q: c)   If the scientists want to estimate the proportion of deer that carry Lyme disease ticks to…

A: We have given that,  Margin of error (E) = 0.02 and confidence level = 90% Then,  We will find the…

Q: For the survey method to be valid, a representative sample of peoplemust be polled. T or F?

A: The survey methodology essentially involves the study of individuals (or a specified group of finite…

Q: A magazine provided results from a poll of 1000 adults who were asked to identify their favorite…

A: Given Information :  A magazine provided results from a poll of 1000 adults who were asked to…

Q: If n=14, (x-bar)-33, and s=9, find the margin of error at a 98% confidence level Give your answer to…

A: We have given that, Sample mean (x̄) = 33, standard deviation (s)= 9 and sample size (n) = 14  Then,…

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: A magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

A: Given: A magazine provided results from a poll of 200 adults who were asked to identify their…

Q: If n=25, 7(x-bar)=48, and s=4, find the margin of error at a 80% confidence level

A: The sample size is 25, sample mean is 48, and sample standard deviation is 4. The degrees of freedom…

Q: A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.…

A: From the given information, The percentage of chocolate pie is 14%. There are 500 respondents.…

Q: For each combination of sample size and sample proportion, find the approximate margin of error for…

A: Given (a) n = 100, p̂ = 0.57 (b) n = 200, p̂ = 0.57.   (c) n = 200, p̂ = 0.40.

Q: A magazine provided results from a poll of 1000 adults who were asked to identify their favorite…

A: There are 1000 respondents 12% chose chocolate pie, and the margin of error is ±4 percent. The value…

Q: What would be the mean of the proportion of homeowners in this sample who prefer a finished…

A: The sampling distribution of p-hat (sample proportion) is approximately normal with mean p and…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given data n=1026 x=520 confidence interval=95%

Q: Use the confidence interval to find the margin of error and the sample mean. (0.456,0.620)

A: The confidence interval is given by (0.456, 0.620) Let M denote the sample mean, And E denote the…

Q: = 360 and p = 0.09, find the margin of error at a 99% confidence level

A:

Q: (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or…

A: The confidence levels are 98% and 80%.

Q: Find the value oft within a) 90% confidence level and n = 10 b) 95% confidence level and n = 6 c)…

A: As per our guidelines we are supposed to answer only 3 sub-parts of any question so I am solving…

Q: Out of 400 people sampled, 68 preferred Candidate A. Based on this, estimate what proportion of the…

A:

Q: If n=12, x¯(x-bar)=47, and s=3, find the margin of error at a 80% confidence level

A: Margin of error (E): The margin of error for sample mean is given by,

Q: Find the value of −zα/2 that corresponds to a confidence level of 89.48​%.

A:

Q: 1(b). At 99% confidence, what is the margin of error?

A: here use given data table

Q: If n=15, (x-bar)=38, and s=8, find the margin of error at a 99% confidence level

A: Margin of error: E=tα2×SE Degrees of freedom: 14(=15-1). Using Excel function, “=T.INV.2T…

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.