Use the t-distribution to find a confidence interval for a difference in means -given the relevant sample results. Give the best estimate for , - , the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 99% confidence interval for a, - using the sample resultsi, = 504, - 103, n = 400 andI; = 450. s = 85, n; = 200 Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate= Margin of error Confidence interval: i to

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