Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y2 are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty' + (6t-1)y' - 6y=7t² e 6t 1 Y₁ = 6t-1, Y₂ = e-6t COL A general solution is y(t) = c₁ (6t-1) + C₂ e - 6t 7 216 (181²-1)

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