Answered: Using direction cosines, the vector P…

Using direction cosines, the vector P in the diagram can be expressed as P= 120 lb y 30° 70° Q = 100 lb O P = (120lb cos 30) i+ (120lb sin 60)j O P = (1201b cos 30°) i + (120lb cos 60°) j

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Angular Momentum

Section: Chapter Questions

Problem 2P: The displacement vectors 42.0 cm at 15.0 and 23.0 cm at 65.0 both start from the origin and form two...

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Scalars and Vectors

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Note: Please provide a simple and step-by-step solution.

Using direction cosines, the vector P in the
diagram can be expressed as
P= 120 lb
y
30°
70°
Q= 100 lb
O P = (1201b cos 30") i+ (120lb sin 60) j
O P = (120lb cos 30') i+ (1201b cos 60) j
O P = (120lb cos 60°) i + (120lb cos 30°) j

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