Using the attached infrared spectroscopy spectrum for the compound Heptanal, identify the functional group and any observed characteristic absorbtions in cm-1. Compare with the attached roadmap for interpreting IR spectra. 105.0902716.111379.361144.80726.13801459.532858.31702928.0860501725.08%T403020100.04000.03000200015001000650.0cm-1Нeptanal Does the compound contain a carbonyl group (C=0)? Check for strong absorption at 1750 to 1650 cm.A. If so, try to identify the type of carbonyl functional group using the information below:I.1. Hydrogen-bonded carboxylic acids should have a broad, strong absorption between 3300 and 2500cm owing to the O-H stretch. There may be multiple bands.2. Aldehydes should have two peaks of medium intensity at about 2780 and 2670 cm owing toaldehydic C-H stretch. One of these may be hidden by aliphatic C-H stretch.Amides usually have the carbonyl absorption around 1670 cm which is at a lower frequency thanmost carbonyl absorptions. If the amide is not tertiary, there should be peaks owing to the N-Hstretch in the vicinity of 3050-3550 cm.B. If possibilities from L.A. (above) have been eliminated, try to identify the type of carbonyl functionfrom the position of the carbonyl absorption itself.1. Anhydrides usually have two peaks in the carbonyl range.Ketones usually have their carbonyl stretching band at a frequency lower than 1725 cm.2.3. Esters usually have their carbonyl stretching band at a frequency higher than 1725 cm.II. If there is no carbonyl absorption, check to see if there are absorptions at frequencies higher than 3100cm. If so, then check below:A. Amines will show N-H stretching bands in the following regions:1. Primary amines (R-NH2) will show two peaks.2. Secondary amines (R2NH) will show one peak.3. Tertiary amines (R;N) will not absorb here.B. Alcohols will show O-H stretching bands in the following regions:1. "Free" O-H stretch at about 3600 cm (broad, strong).2. "Hydrogen-bonded" O-H stretch at about 3400 cm? (broad, strong).II. Check to see if the compound contains triple bonds.A. Acetylenes will have a variable C=C stretching band at about 2100-2260 cm.B. Nitrites (C=N) will have a similar band at about 2200-2300 cm?.IV. Next, consider the C-H stretching region.A. Aliphatic C-H stretch usually gives an intense absorption at slightly less than 3030 cm.B. Aromatic and alkene C-H stretch usually gives much weaker absorption at slightly more than 3030 cm.V. Check to see if the compound contains C=C bonds.A. Alkenes will show an absorption owing to C=C stretching in the vicinity of 1660 cm. This may be arather weak band.VI. Check to see if the compound contains aromatic benzene rings. The following are useful:A. The presence of large absorption bands in the 650 to 900 cm range is a good indication of a benzenering. The position of these bands is useful in determining the substitution pattern. They are due to C-Hout-of-plane bending.B. Several weak absorptions should be present between 1667 and 2000 cm.C. Most aromatic compounds will show four bands between 1429 and 1667 cm due to C=C vibrations inthe benzene ring. They may appear as "shoulders".D. An aromatic compound with five adjacent hydrogen atoms will absorb strong absorptions at 750 and700 cm.An aromatic compound with four adjacent hydrogen atoms will absorb strongly only near 750 cm?.F. Thus, if the compound does not absorb strongly near 700 cm' it cannot be a monosubstitutedbenzene compound.EVII. Check the C-H bending region for the following:A. The presence of two strong peaks at about 1450 and 1375 cm usually indicates the presence of oneor more methyl groups.B. Two methyls on the same carbon (geminal dimethyl) or at-butyl group usually causes the peak at 1375cm to be split into a doublet.VIII. For more detail, check IR tables and references.Infrared SpectraNote that spectra of the same compound taken on different instruments may 'look' different because of thedifferent scales used. The graph below uses the scale found on the instruments in Chem 237/238 withdifferent linear scales above and below 2000 cm*.Note that the spectra in McMurry are not scaled in this manner. Compare the peak frequencies, not the 'look'.WAVE NUMBER (CM-1)400030002000IS001000 400Free OCECCENNH (singla) nd-NH : laH-bended ocartenylie -SINGLE BONDSOINGERPRINT REGIONEXTENDS EOWN TO 00 CM)BONDS TO HYDROGENDOUBLETRIPLEIONDSBONDSStronger bonds absorb energy at higher frequencies (wave numbers):Triple bonds Double bonds Single bondsUse the fignerprint region to differentiate between different compuonds with the same funtionalities.

Question

Using the attached infrared spectroscopy spectrum for the compound Heptanal, identify the functional group and any observed characteristic absorbtions in cm-1. Compare with the attached roadmap for interpreting IR spectra. 105.0902716.111379.361144.80726.13801459.532858.31702928.0860501725.08%T403020100.04000.03000200015001000650.0cm-1Нeptanal Does the compound contain a carbonyl group (C=0)? Check for strong absorption at 1750 to 1650 cm.A. If so, try to identify the type of carbonyl functional group using the information below:I.1. Hydrogen-bonded carboxylic acids should have a broad, strong absorption between 3300 and 2500cm owing to the O-H stretch. There may be multiple bands.2. Aldehydes should have two peaks of medium intensity at about 2780 and 2670 cm owing toaldehydic C-H stretch. One of these may be hidden by aliphatic C-H stretch.Amides usually have the carbonyl absorption around 1670 cm which is at a lower frequency thanmost carbonyl absorptions. If the amide is not tertiary, there should be peaks owing to the N-Hstretch in the vicinity of 3050-3550 cm.B. If possibilities from L.A. (above) have been eliminated, try to identify the type of carbonyl functionfrom the position of the carbonyl absorption itself.1. Anhydrides usually have two peaks in the carbonyl range.Ketones usually have their carbonyl stretching band at a frequency lower than 1725 cm.2.3. Esters usually have their carbonyl stretching band at a frequency higher than 1725 cm.II. If there is no carbonyl absorption, check to see if there are absorptions at frequencies higher than 3100cm. If so, then check below:A. Amines will show N-H stretching bands in the following regions:1. Primary amines (R-NH2) will show two peaks.2. Secondary amines (R2NH) will show one peak.3. Tertiary amines (R;N) will not absorb here.B. Alcohols will show O-H stretching bands in the following regions:1. &#34;Free&#34; O-H stretch at about 3600 cm (broad, strong).2. &#34;Hydrogen-bonded&#34; O-H stretch at about 3400 cm? (broad, strong).II. Check to see if the compound contains triple bonds.A. Acetylenes will have a variable C=C stretching band at about 2100-2260 cm.B. Nitrites (C=N) will have a similar band at about 2200-2300 cm?.IV. Next, consider the C-H stretching region.A. Aliphatic C-H stretch usually gives an intense absorption at slightly less than 3030 cm.B. Aromatic and alkene C-H stretch usually gives much weaker absorption at slightly more than 3030 cm.V. Check to see if the compound contains C=C bonds.A. Alkenes will show an absorption owing to C=C stretching in the vicinity of 1660 cm. This may be arather weak band.VI. Check to see if the compound contains aromatic benzene rings. The following are useful:A. The presence of large absorption bands in the 650 to 900 cm range is a good indication of a benzenering. The position of these bands is useful in determining the substitution pattern. They are due to C-Hout-of-plane bending.B. Several weak absorptions should be present between 1667 and 2000 cm.C. Most aromatic compounds will show four bands between 1429 and 1667 cm due to C=C vibrations inthe benzene ring. They may appear as &#34;shoulders&#34;.D. An aromatic compound with five adjacent hydrogen atoms will absorb strong absorptions at 750 and700 cm.An aromatic compound with four adjacent hydrogen atoms will absorb strongly only near 750 cm?.F. Thus, if the compound does not absorb strongly near 700 cm' it cannot be a monosubstitutedbenzene compound.EVII. Check the C-H bending region for the following:A. The presence of two strong peaks at about 1450 and 1375 cm usually indicates the presence of oneor more methyl groups.B. Two methyls on the same carbon (geminal dimethyl) or at-butyl group usually causes the peak at 1375cm to be split into a doublet.VIII. For more detail, check IR tables and references.Infrared SpectraNote that spectra of the same compound taken on different instruments may 'look' different because of thedifferent scales used. The graph below uses the scale found on the instruments in Chem 237/238 withdifferent linear scales above and below 2000 cm*.Note that the spectra in McMurry are not scaled in this manner. Compare the peak frequencies, not the 'look'.WAVE NUMBER (CM-1)400030002000IS001000 400Free OCECCENNH (singla) nd-NH : laH-bended ocartenylie -SINGLE BONDSOINGERPRINT REGIONEXTENDS EOWN TO 00 CM)BONDS TO HYDROGENDOUBLETRIPLEIONDSBONDSStronger bonds absorb energy at higher frequencies (wave numbers):Triple bonds > Double bonds > Single bondsUse the fignerprint region to differentiate between different compuonds with the same funtionalities.

Accepted Answer

The compound is an aldehyde and its structure is given below :

Heptanal
There are two…