# Using the existence and uniqueness theorem for second order linear ordinary differential equations, find the largest interval in which the solution to the initial value is certain to exist.t(t2-4)y"-ty'+3t2y=0, y(1)=1, y'(1)=3

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Using the existence and uniqueness theorem for second order linear ordinary differential equations, find the largest interval in which the solution to the initial value is certain to exist.

t(t2-4)y"-ty'+3t2y=0, y(1)=1, y'(1)=3

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Step 1

The given initial value problem is:

Step 2

Existence and Uniqueness Theorem: help_outlineImage TranscriptioncloseIf p(x),q(x) and g(x) are continuous on the interval [a, b], then the second order differential equation y'p(x)xy=g(x), y(x)y, y(x,)= has a unique solution defined for all x in [a, b]. fullscreen
Step 3

Redefine the differential e...

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