Using the substitutions X =u+2, y=w+2; dx= du, dy= dw, the DE with linear coefficients (x +y-4)dx – (3x-y-4)dy=0 reduces to A (u+ w)du + (3u – w)dw=0 B (u+w+4)du+(3u-w- 4)dw=0 (c) (u+w+2)du+(3u-w-2)dw=0 (u+w-4)du+(3u-w- 4)dw=0

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