Using the table showing partial pressures for the formation of ammonia and corresponding equilibrium constants, show that at 101 bar, apparent equilibrium constants equals 0.0072 and the thermodynamic equilibrium constant equals 0.0064.

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Chapter13: Fundamental Equilibrium Concepts
Section: Chapter Questions
Problem 101E: A 0.010 M solution of the weak acid HA has an osmotic pressure (see chapter on solutions and...
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Using the table showing partial pressures for the formation of ammonia and corresponding equilibrium constants, show that at 101 bar, apparent equilibrium constants equals 0.0072 and the thermodynamic equilibrium constant equals 0.0064.

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Table 9.1
Equilibrium Constants for the Reaction !N2(g)+ {H2(g)=NH3(g) at 450°C
Total pressure/bar
PNH,
PH:
Kp
K,
K¢(KpK;)
10.2
0.204
2.30
7.67
0.0064
0.994
0.0064
30.3
1.76
6.68
21.9
0.0066
0.975
0.0064
50.6
4.65
10.7
35.2
0.0068
0.95
0.0065
101.0
16.6
19.4
65.0
0.0072
0.89
0.0064
302.8
108
42.8
152
0.0088
0.70
0.0062
606
326
56.5
223
0.0130
0.50
0.0065
*Data from A. J. Larson, J. Am. Chem. Soc. 46, 367 (1924).
K, Thermodynamic equilibrium constant
K, Apparent equilibrium constant ( value changes with P at given T)
At low pressures K, close to K, (indicates ideal behavior)
K, always the same (small deviations due to calculations in fugacity)
Transcribed Image Text:Table 9.1 Equilibrium Constants for the Reaction !N2(g)+ {H2(g)=NH3(g) at 450°C Total pressure/bar PNH, PH: Kp K, K¢(KpK;) 10.2 0.204 2.30 7.67 0.0064 0.994 0.0064 30.3 1.76 6.68 21.9 0.0066 0.975 0.0064 50.6 4.65 10.7 35.2 0.0068 0.95 0.0065 101.0 16.6 19.4 65.0 0.0072 0.89 0.0064 302.8 108 42.8 152 0.0088 0.70 0.0062 606 326 56.5 223 0.0130 0.50 0.0065 *Data from A. J. Larson, J. Am. Chem. Soc. 46, 367 (1924). K, Thermodynamic equilibrium constant K, Apparent equilibrium constant ( value changes with P at given T) At low pressures K, close to K, (indicates ideal behavior) K, always the same (small deviations due to calculations in fugacity)
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