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- give the python codes for the following: heres the document for the car.csv https://mymailmapuaedu-my.sharepoint.com/:x:/g/personal/cdtalag_mymail_mapua_edu_ph/EQw3kQj7p0dAiyyQHr_9rlgByETAK13lQ7I9pWZNnZO7Hg?e=mCyccN pls help me asapHow can I modify this C script so that instead of a single character d or w, it takes the specific string "Delta" or "Wye" as user input to choose either option in the script? I believe the only header that should need to be added is string.h, please don't add anything else I won't be able to use it. My script: #include<stdio.h>#include<math.h>int main(){//4. Prompt the user for repetition of the process.char ch = 'y';char network='a';float za,zb,zc,zac,zbc,zcc,z1,z2,z3,z1c,z2c,z3c;float zaxb,zbxc,zaxc,zd,zdc,z1z3,z1z2,z2z3;float zaxbc,zbxcc,zaxcc,z1z3c,z1z2c,z2z3c,zt,ztc;while(ch=='y' || ch=='Y'){//1. ask the user whether it is a Delta or Wye network.printf("\nWhat kind of network? Enter D for delta or W for Wye network:\n\n");scanf("%s",&network);//2. ask the user to type in values (for impedances)//3. make the conversion (Delta to Wye or Wye to Delta)//Delta Network ==> Wyeif(network=='d'||network=='D'){printf("\nWhat are the real values of the impedances…Dan’s recently announced that he’s teaching n top-secret courses next semester. Instead of enrolling in them through ACORN, students need to email Dan to express their interests. These courses are numbered from 1 to n in some arbitrary order. In particular, if a student named s is interested in taking a course c, they need to sendanemailtoDancontainingthemessagec s.Notethatifastudentis interested in taking multiple courses, they need to send multiple emails, one per course. Uponreceivingamessagec s,Danlooksatthelistofstudentsalreadyenrolledin course c. If there’s already a student on the list whose name is too similar to s, Dan assumes s is the same student and ignores the message. Otherwise, he enrolls s in the course. Dan considers two names too similar if and only if they have the same length and differ in at most one letter (note that “a” and “A” are considered the same letter). For example, “Josh” and “Josh” are too similar. “Sam” and “CaM” are too similar as well. However,…
- Question 4: Ask the user for an account balance. Show, in descending order, all the accounts that have a balance greater than what the user input. Each entry is int, string, long, double, boolean (name length, name, credit card number, balance, cashback). File that was given https://bes.hypergrade.com/api/user/file/1923815 NOTE: It has to be printed and sorted by Balance (Higher value on top) =========================================== File one --------------------- public class Person implements Comparable<Person> {private long account;private String name;private double balance;private boolean YN;public Person(String name, long account, double balance, boolean YN) {this.account = account;this.balance = balance;this.YN = YN;this.name = name;}@Overridepublic int compareTo(Person per) {int compare = name.compareTo(per.name);if (compare == 0) {return 0;} else if (compare < 1) {return -1;} else {return 1;}}/*** @return the balance*/public double getBalance() {return…Kyv cvkkvij ze kyv wcrx riv vetipgkvu ze kyv jrdv nrp rj kyzj dvjjrxv... The a-zA-Z letters in the middle of curly brackets are converted in the same way as above. { nF71aRxw2EnCVdtWVDgvEVhcm8T.0cE5nJDpZqN } How are they converted? and what encryption type is used?Transcribed Image Text #include<stdio.h> #include<string.h> #include<conio.h> #include<stdlib.h> int i; char n=1,username[16],password[ 30],ch; void welcome() { system ("@cls||clear"); printf("\t\tWECOME TO MY SITE\n"); } int main() { while(n<=3) { welcome(); printf("\n\NLOGIN HERE!"); printf("\n\nUSERNAME : "); scanf ("%s",&username); printf("PASSWORD: "); for (i=0;i<16;i++) { ch = getch(); if(ch==13) { password[i]='\0'; break; password[i]=ch; printf("*"); password[i]='\0'; printf("\n\n"); system("pause"); if(strcmp(username, "rolan")==0) if(strcmp(password, "12345")==0) { welcome(); printf("\n\NYOU'VE LOGIN SUCCESSFULLY!"); break; else welcome(); printf("\n\nWRONG PASSWORD. You have %d attempt/s left...",3-n); else welcome(); printf("\n\NUSER DOESN'I EXIST. You have %d attempt/s left...",3-n); getch(); n++; if(n==4) { welcome(); printf("\nSORRY! YOU CAN'T LOGIN."); break; getch(); } }
- Assume that you are working with the following history list: 37 mail zach 38 cd /home/sam/correspondence/business/cheese_co 39 less letter.0321 40 vim letter.0321 41 cp letter.0321 letter.0325 42 grep hansen letter.0325 43 vim letter.0325 44 lpr letter* 45 cd ../milk_co 46 pwd 47 vim wilson.0321 wilson.0329 a) How can you prevent a command from sending output to the terminal when you start it in the background? b) What can you do if you start a command in the foreground and later decide that you want it to run in the background?What type of names does the following command match? [mam-p@voyager FINAL]$ ls /usr/share/man/man1/*[aeiou]*[aeiou]*[aeiou]*[aeiou]*[aeiou]* Group of answer choices a. names containing at least five lowercase vowels b. names that contain five occurrences of the string "aeiou" c. none of these d. names containing at least five lowercase vowels in alphabetical order e. names containing exactly five lowercase vowelsHere is the multi-line text:21112021#Mr. Ade Saputra, ade.saputra.1@gmail.com0812-345678902122021#Mrs. Fefe, mrsfefe123_0@binus.edu0813-1234568803122021#Ms. Jessica, jessicamiss@hotmail.com0878-9876543209122021#Mrs Essy Yosita, 880gr233500 essyyosita@yahoo.com0838-55555511122021#Mrs. Meily, mily123456@ymail.com0888-888888813122021#Ms. Widya Natali, widyanataliemail@binus.ac.id0811-1122334414122021#Mr. Excelio, excelio@celio.com0898-9898989826122021#Ms. Deby Nath, nath_deby@outlook.com0834-2235485729122021#Mr. Hando Tan, hando.tan@mail.co.id0252-554321 There are sub-data:• Join Date• Name• Email• No Telp Please help me with: i. Create a Regex pattern to be able to retrieve sub-data from the text above! ii. Explain how Regex can match with sub-data?
- OBX Cart Rentals has created a website for customer access. They are trying todetermine a reasonably secure number of available passwords. They have decided toallow upper case letters, lower case letters, digits (0 – 9), and the three pecialcharacters: $, ! ?. Find the number of possible 6 character passwords given each of theconditions (Note: you MUST simplify completely.)a. The password must begin with a letter (either upper or lower case)i. repetitions permittedii. repetitions not permittedb. The password must begin with a letter and end with a special character ($, !, ?):i. repetitions permittedii. repetitions not permittedhello could you help me to modify my code below 1. Round the total sum of the order to the nearest 5 sen. refer https://www.bnm.gov.my/misc/-/asset_publisher/2BOPbOBfILtL/content/about-the-rounding-mechanism #include <iostream> using namespace std; void menu(){ cout << "******Welcome to the Farhan's Restaurant******" << endl; cout<<"_________________________________________________"<<endl; cout<<"No. Menu Price"<<endl; cout<<"1. Cheese Burger RM 8"<<endl; cout<<"2. Chicken Wings(6 pieces) RM 10"<<endl; cout<<"3. 12\" Pepperoni Pizza RM 20"<<endl; cout<<"4. Fries RM 5"<<endl; cout<<"5. Onion Rings RM 6"<<endl; cout<<"6. Pepsi RM 2"<<endl; cout<<"7. Mineral Water RM 3"<<endl; } main(){ string phone; //we use…(C-PROGRAMMING) Can someone help figure out what I'm doing wrong in my script? I'm trying to prompt the user to choose 1 of 2 total udfs and then display values but the 1st udf only shows 0.000 for all the float values and the 2nd udf behaves similarly. I need to stick to the stdio.h and math.h headers, please. #include <stdio.h> #include <math.h> void compute(int n){ float sum=0;float arr[100]; int i; float average, variance = 0.0, standard_deviation; for (i = 0; i < n; ++i) { sum = sum + arr[i] ; average = sum / n; variance += pow(arr[i] - average, 2); variance = variance / n; printf("\nWith the provided values, the average is %.2f and variance is %.2f. \n", average, variance, standard_deviation); { if (arr[i] > average) printf("%.2f, which is larger than our average of %.2f. \n", arr[i], average); else printf("%.2f, which is less than our average…