Utt = c² Uxx; u(0, t) = 0, with the initial conditions 7πχ 2L u(x,0) = 3 sin 0 < x < L, t> 0 ux (L, t) = 0, ut(x, 0) = 17 sin 3TX 2L 0< x < L.

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Chapter2: Second-order Linear Odes
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Can u Solve the vibrating string probity of length L with ends fixed at x = 0 and free at x = L respectively

 

Utt = c² Uxx
u(0, t) = 0,
with the initial conditions
7TX
2L
u(x,0) = 3 sin
0 < x < L₂t> 0
ux (L, t) = 0,
ut(x,0) = 17 sin
3πTX
2L
0 < x < L.
Transcribed Image Text:Utt = c² Uxx u(0, t) = 0, with the initial conditions 7TX 2L u(x,0) = 3 sin 0 < x < L₂t> 0 ux (L, t) = 0, ut(x,0) = 17 sin 3πTX 2L 0 < x < L.
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