V01 (in volt) due to V1 only= a. -0.022367846221057 O b. -0.011183923110529 c. 0 O d. -0.033551769331586 (Note that V0=VO1+V02, where Vo1 is due to V1 and Vo2 is due to 1) VO2 (in volt) due to 1 only= a. -8.2984709480122 O b. -4.1492354740061 C. -2.4895412844037 O d. -10.788012232416 (Note that VO=V01+V02, where Vo1 is due to V1 and Vo2 is due to 11) then Vo (in volt)= Dower on D1 lip wvatt)

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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V01 (in volt) due to V1 only=
a. -0.022367846221057
b. -0.011183923110529
c. 0
d. -0.033551769331586
(Note that VO=V01+V02, where Vo1 is due to V1 and Vo2 is due to 1)
V02 (in volt) due to 11 only=
a. -8.2984709480122
b. -4.1492354740061
C. -2.4895412844037
d. -10.788012232416
(Note that V0=V01+V02, where Vo1 is due to V1 and Vo2 is due to 1)
then Vo (in volt)=
Power on R1 (in watt) =
Transcribed Image Text:V01 (in volt) due to V1 only= a. -0.022367846221057 b. -0.011183923110529 c. 0 d. -0.033551769331586 (Note that VO=V01+V02, where Vo1 is due to V1 and Vo2 is due to 1) V02 (in volt) due to 11 only= a. -8.2984709480122 b. -4.1492354740061 C. -2.4895412844037 d. -10.788012232416 (Note that V0=V01+V02, where Vo1 is due to V1 and Vo2 is due to 1) then Vo (in volt)= Power on R1 (in watt) =
For R1=32 Q, R2=81 Q, R3=106 N, V1=8 V, 11=28 A & K1=4.5, use the principle of superposition to find :
R2
R3
vi +
Il
R1
Transcribed Image Text:For R1=32 Q, R2=81 Q, R3=106 N, V1=8 V, 11=28 A & K1=4.5, use the principle of superposition to find : R2 R3 vi + Il R1
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