V2 i2 R1 R3 Vi in R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R, (i, – i; ) + R, (i, – i, ) = V, R, i, + R, (i, –i, )+ R, (i̟ – i, ) =V½ R, i, + R, (i, – i, )+ R, (i, – i, ) = V, where R is the resistance and i is the current. If R1=20, R2= 10, R3=25, = 10, Rs= 30, Vi= 0, V2=0 and V3=200, Solve the system of linear equations above for i,, i, and i, by Gauss elimination R4

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V2
i2
R1
R3
V1 +
in
R4
R2
i3
R5
V3
The analysis of the voltage, V for the electrical circuit shown in figure given above
can be expressed in the following three equations:
R, (i, – i, ) + R, (i, - i; ) =V
R, i, + R, (i, –i, )+ R, (i, – i, ) =V½
R, i, + R, (i, – i, )+R, (i, – i, ) = V3
where R is the resistance and i is the current. If R1= 20, R2= 10, R3=25,
= 10, Rs= 30, Vi= 0, V2=0 and V3=200,
Solve the system of linear equations above for i, i, and i, by Gauss elimination
R4
method.
Transcribed Image Text:V2 i2 R1 R3 V1 + in R4 R2 i3 R5 V3 The analysis of the voltage, V for the electrical circuit shown in figure given above can be expressed in the following three equations: R, (i, – i, ) + R, (i, - i; ) =V R, i, + R, (i, –i, )+ R, (i, – i, ) =V½ R, i, + R, (i, – i, )+R, (i, – i, ) = V3 where R is the resistance and i is the current. If R1= 20, R2= 10, R3=25, = 10, Rs= 30, Vi= 0, V2=0 and V3=200, Solve the system of linear equations above for i, i, and i, by Gauss elimination R4 method.
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