Answered: Vcc = 16 V 3.9 k2 39 k2 Ht IµF B = 100…

Engineering

Electrical Engineering

Vcc = 16 V 3.9 k2 39 k2 Ht IµF B = 100 .= 50 k£2 4.7 k2 1.2 k2 10µF

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter19: Special-purpose Outlets-water Pump, Water Heater

Section19.2: Water Heater Branch Circuit

Problem 8R: For residential water heaters, the Consumer Product Safety Commission suggests a maximum temperature...

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Concept explainers

BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.

Question

Question No. 1: A circuit based on an amplifier shown in Fig.1 is installed in location
where the temperature varies largely. This variation produces unwanted changes in the
output signal. Being electronic engineer suggest a suitable change in the circuit so the
output should be stable as well as amplified. Justify your answer by analyzing the
circuit.Discuss what will be the effect of suggested changes if the BJT is replaced by any
FET.

Vcc = 16 V
3.9 k2
39 k2
1µF
IµF
Z,
V, o
B = 100
T,= 50 k2
4.7 k2
Z
1.2 kQ
10 μF

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