Vcc Ic 2.2 k2 RB + VCE = 7.2 V B = 20 µA %3D IIE = 4 mA 812 Kohm 100 Kohm

Electric Motor Control
10th Edition
ISBN:9781133702818
Author:Herman
Publisher:Herman
Chapter32: Two-speed, One-winding (consequent Pole) Motor Controllers
Section: Chapter Questions
Problem 6SQ: Describe the operation of Figure 325 (B) by adding jumper wire A to the original circuit.
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3.solve for RB

VcC
Ic
2.2 kN
RB
VCE = 7.2 V B
Iz = 20 µA
%3D
Ig = 4 mA
812 Kohm
100 Kohm
900 Kohm
O 763 kohm
Transcribed Image Text:VcC Ic 2.2 kN RB VCE = 7.2 V B Iz = 20 µA %3D Ig = 4 mA 812 Kohm 100 Kohm 900 Kohm O 763 kohm
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