Vcc Ic 2.2 k2 RB + VCE = 7.2 V B = 20 µA %3D IIE = 4 mA 812 Kohm 100 Kohm
Vcc Ic 2.2 k2 RB + VCE = 7.2 V B = 20 µA %3D IIE = 4 mA 812 Kohm 100 Kohm
Chapter32: Two-speed, One-winding (consequent Pole) Motor Controllers
Section: Chapter Questions
Problem 6SQ: Describe the operation of Figure 325 (B) by adding jumper wire A to the original circuit.
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3.solve for RB
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