Question
Asked Sep 5, 2019
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Verify that the indicated function is an explicit solution of the given differential equation. Assume an appropriate interval I. 

d^2y/dx^2 - 6dy/dx +13y =0 ; y=e^(3x)cos2x

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Expert Answer

Step 1

The function is given as: 

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y ecos2x

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Step 2

The differential equation is given as:

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d'y -6. dy -+13y 0

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Step 3

To verify: The given function is the explicit solution o...

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Differentiate y = e* cos2x with respect to x. dy d 3x cos 2x dx d d = cOs 2x dx d 3x +e(cos 2x(Apply product rule) dx (Apply chain rule) cos 2x (3e+e** (-2 sin 2x) = 3e3* cos2x -2e3* sin 2x Thus ay3e3* cos 2x-2e** sin 2x.

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Advanced Math

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