Asked Nov 14, 2019

Vinegar contains (among other things) acetic acid. What is the molarity of acetic acid (HC2H3O2) in vinegar that contains 4.0% acetic acid by weight and having a density of 1.02 g/mL?


Expert Answer

Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;


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Moles of solute Molarity volume of solution in L Mass of solute ing Moles Molar mass of solute (g/mol)

Step 2

Mass percentage of acetic acid in vinegar = 4.0 %

Hence 4.0 g of acetic acid is present in 100 g of solution

Molar mass of acetic acid = 60 g/mol


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Mass of solute in g Moles Molar mass of solute (g/mol) 4.0 g Moles 60.0 g/mol Moles 0.07 moles

Step 3

Density of solution = 1.02 g/mL

Mass of solution = 100 g (from 4.0 ...


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mass Volume density 100 g Volume 1.02 g/mL Volume 98 mL


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