Volume the NaOh 0.100 M dispensed 17.10 ml pH 9.63. Calculate the molarity of HCl solution (15 ml of Hydrochloric acid + 85 ml of water= 100 ml of solution) using the volume dispensed in your titration 17.10 ml of NaOH. Find the equivalence point in the graph. The ph equals the pKa at the half equivalence point? What is the pKa of HCl?

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Volume the NaOh 0.100 M dispensed 17.10 ml pH 9.63. Calculate the molarity of HCl solution (15 ml of Hydrochloric acid + 85 ml of water= 100 ml of solution) using the volume dispensed in your titration 17.10 ml of NaOH. Find the equivalence point in the graph. The ph equals the pKa at the half equivalence point? What is the pKa of HCl?

Volume
pH
1.78
Titration of a Hydrochloric acid with NaOH
1
1.81
14
1.84
3
1.87
12
4
1.91
1.95
10
6
2
7
2.04
8
2.09
8
9.
2.14
10
2.21
6.
11
2.28
12
2.37
4
13
2.47
14
2.61
15
2.81
2
16
3.16
17.1
9.63
18.1
10.97
10
15
20
25
23.1
11.69
Volume of titrant (NaOH)
Hd
LO
Transcribed Image Text:Volume pH 1.78 Titration of a Hydrochloric acid with NaOH 1 1.81 14 1.84 3 1.87 12 4 1.91 1.95 10 6 2 7 2.04 8 2.09 8 9. 2.14 10 2.21 6. 11 2.28 12 2.37 4 13 2.47 14 2.61 15 2.81 2 16 3.16 17.1 9.63 18.1 10.97 10 15 20 25 23.1 11.69 Volume of titrant (NaOH) Hd LO
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