Question

Asked Nov 16, 2019

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Water is poured into a container that has a leak. The mass *m* of the water is given as a function of time *t* by *m* = 4.9*t*^{0.8} - 2.6*t* + 18, with *t* ≥ 0, *m* in grams, and *t* in seconds. **(a)** At what time is the water mass greatest, and **(b)** what is that greatest mass? What is the rate of mass change at **(c)** *t* = 1.9 s and **(d)** *t* = 4.9 s?

Step 1

Write the given function of time for the mass of the water, and differentiate with respect to time.

Step 2

**(a)**

The water mass will be greatest when the rate of mass change will be equal to zero. Thus, time for the greatest water mass can be calculated as,

Step 3

**(b)**

Substitute the value of time for the greatest water mass in the given ...

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