We already know we can do the following problem using u-substitution, with u sin (-5z) cos(-5z) dz

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter47: Applications Of Formulas To Cutting Speed, Revolutions Per Minute, And Cutting Time
Section: Chapter Questions
Problem 47A
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We already know we can do the following problem using u-substitution, with u = sin(-5z)
sin (-52) cos(-5z) dz =
We see that sin (-5z) cos*(-5z) dz is solved similarly, because
O A. che exponent of sin is odd.
B. the exponent of cos is odd.
OC. None of the above
So we'll stll use u-substitution with u = sin(-5z), after first rewriting cos"(-5z) = cos"(–5z) cos(-52) and using a trig identity. Select the trigonometric identity needed to solve this problem.
OA. 1+ cot u= csc u
1+ cos(2u)
B. cos u
C. sin u=
D. tan u+1= sec u
E. sin u+ cos u =1
E. None of the above
Finally, put it all together to calculate sin (-5z) cos"(-5z) dz =
Hints will appear after 3, 6, 9, and 12 attempts.
Show hint
The integral involves sinu and cosu where the exponent of cosu is an odd, positive integer, namely, 3. So we factor out a copy of cos(-5x) and use the identity sin2u+cos2u-1 to turn the remaining cos2(-5x) into an expression involving sin2(-5x).
Show hint
Thus the integral can be rewritten as fin4(-5x)cos3(-5x)dx- fin4(-5x)cos2(-5x)cos(-5x)dx - kin4(-5x)(1-sin2(-5x))cos(-5x)dx and we use u-substitution.
Transcribed Image Text:We already know we can do the following problem using u-substitution, with u = sin(-5z) sin (-52) cos(-5z) dz = We see that sin (-5z) cos*(-5z) dz is solved similarly, because O A. che exponent of sin is odd. B. the exponent of cos is odd. OC. None of the above So we'll stll use u-substitution with u = sin(-5z), after first rewriting cos"(-5z) = cos"(–5z) cos(-52) and using a trig identity. Select the trigonometric identity needed to solve this problem. OA. 1+ cot u= csc u 1+ cos(2u) B. cos u C. sin u= D. tan u+1= sec u E. sin u+ cos u =1 E. None of the above Finally, put it all together to calculate sin (-5z) cos"(-5z) dz = Hints will appear after 3, 6, 9, and 12 attempts. Show hint The integral involves sinu and cosu where the exponent of cosu is an odd, positive integer, namely, 3. So we factor out a copy of cos(-5x) and use the identity sin2u+cos2u-1 to turn the remaining cos2(-5x) into an expression involving sin2(-5x). Show hint Thus the integral can be rewritten as fin4(-5x)cos3(-5x)dx- fin4(-5x)cos2(-5x)cos(-5x)dx - kin4(-5x)(1-sin2(-5x))cos(-5x)dx and we use u-substitution.
We already know we can do the following problem using u-substitution, with u = sin(-5z)
sin (-5a) cos(-52) dr
=
We see that
sin (-5z) cos (-5r) dr is solved similarly, because
A. the exponent of sin is odd.
eB. the
exponent
of cos is odd.
O C. None of the above
So we'll still use u-substitution with u = sin(-5r), after first rewriting cos (-5z) = cos' (-5z) cos(-5z) a
csc
1+ cos(2u)
OA. 1+ cot u=
O B. cos u =
2
1- cos(2u)
OC. sin
OD. tan u +1= sec?
eE. sin
u+ cos u =1
OF. None of the above
Finally, put it all together to calculate sin (-5z) cos (-5x) dr
Hints will appear after 3, 6, 9, and 12
attempts.
Transcribed Image Text:We already know we can do the following problem using u-substitution, with u = sin(-5z) sin (-5a) cos(-52) dr = We see that sin (-5z) cos (-5r) dr is solved similarly, because A. the exponent of sin is odd. eB. the exponent of cos is odd. O C. None of the above So we'll still use u-substitution with u = sin(-5r), after first rewriting cos (-5z) = cos' (-5z) cos(-5z) a csc 1+ cos(2u) OA. 1+ cot u= O B. cos u = 2 1- cos(2u) OC. sin OD. tan u +1= sec? eE. sin u+ cos u =1 OF. None of the above Finally, put it all together to calculate sin (-5z) cos (-5x) dr Hints will appear after 3, 6, 9, and 12 attempts.
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