We compare the values of Q and K to predict the direction in which a reaction will proceed toward equilibrium. Qc < Kc then: Qc > Kc then Qc = Kc then more reactant forms; more products form; there is no net change more products form; more reactant forms; there is no net change there is no net change; more reactant forms; more products form O more products form; there is no net change; more reactant forms

We compare the values of Q and K to predict the direction in which a reaction will proceed toward equilibrium. Qc < Kc then: Qc > Kc then Qc = Kc then more reactant forms; more products form; there is no net change more products form; more reactant forms; there is no net change there is no net change; more reactant forms; more products form O more products form; there is no net change; more reactant forms

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.18PAE: The reaction, 3 H2(g) + N2(g) (g), has the fol lowing equilibrium constants at the temperatures...

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