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We have a large dataset which we denote by D1, with values x1, x2, x3, ..., xN. Its mean is denoted by m. We create a new dataset D2 as follows: x1-m, x2-m, x3-m, .., xN-m (that is, we subtract the mean from every data point). Then we create a new dataset by dividing every value in D2 by number 5. (so note that we said D2, not D1). What is the mean of D3? Group of answer choices 5 m m/5 m/ 25

We have a large dataset which we denote by D1, with values x1, x2, x3, ..., xN. Its mean is denoted by m. We create a new dataset D2 as follows: x1-m, x2-m, x3-m, .., xN-m (that is, we subtract the mean from every data point). Then we create a new dataset by dividing every value in D2 by number 5. (so note that we said D2, not D1). What is the mean of D3? Group of answer choices 5 m m/5 m/ 25

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 14PPS
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We have a large dataset which we denote by D1, with values x1, x2, x3, ..., xN. Its mean is denoted by m. We create a new dataset D2 as follows: x1-m, x2-m, x3-m, ..., xN-m (that is, we subtract the mean from every data point). Then we create a new dataset by dividing every value in D2 by number 5. (so note that we said D2, not D1). What is the mean of D3? Group of answer choices 5 m m/5 m/ 25
Transcribed Image Text:We have a large dataset which we denote by D1, with values x1, x2, x3, ..., xN. Its mean is denoted by m. We create a new dataset D2 as follows: x1-m, x2-m, x3-m, ..., xN-m (that is, we subtract the mean from every data point). Then we create a new dataset by dividing every value in D2 by number 5. (so note that we said D2, not D1). What is the mean of D3? Group of answer choices 5 m m/5 m/ 25
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