We have a steel shaft that rotates at 3 Hz shown in the figure. The shaft is divided into two segments; AB and BC. Segment Ab is a solid shaft that has a diameter derived from the equation x² + y² = 625 expressed in millimeters. For segment BC, we have a solid section with dimensions derived from the equation 25x² + 36y²-22500 = 0 expressed in millimeters. Find the maximum shear stress and the angle of rotation of point C relative to point A. Use G = 83 GPa 55 kNccw 30 kNccw B 85 kN 2 C A 6 m 3 m

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.7.12P
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We have a steel shaft that rotates at 3 Hz shown in the figure. The shaft is divided
into two segments; AB and BC. Segment Ab is a solid shaft that has a diameter
derived from the equation x² + y² = 625 expressed in millimeters. For segment
BC, we have a solid section with dimensions derived from the equation 25x² +
36y²-22500 = 0 expressed in millimeters. Find the maximum shear stress and
the angle of rotation of point C relative to point A. Use G = 83 GPa
55 kNccw
30 kNccw
B
85 kN
C
A
6 m
3 m
Transcribed Image Text:We have a steel shaft that rotates at 3 Hz shown in the figure. The shaft is divided into two segments; AB and BC. Segment Ab is a solid shaft that has a diameter derived from the equation x² + y² = 625 expressed in millimeters. For segment BC, we have a solid section with dimensions derived from the equation 25x² + 36y²-22500 = 0 expressed in millimeters. Find the maximum shear stress and the angle of rotation of point C relative to point A. Use G = 83 GPa 55 kNccw 30 kNccw B 85 kN C A 6 m 3 m
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