We performed the experiment to measure the thermal conductivity of 2 materials (Brass & Steel) in the laboratory and measured the following tabulated values: Material 1- BRASS (Diameter = 25mm)
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Q: Material 1- BRASS The below shown graph is drawn from the tabulated values of steel which we…
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A: Temperature (T) = 3700 k area (A) = 10-4 m2emissivity (e) = 0.120σ = 5.67×10-8 W/(m2.k4)
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Q: The below shown graph is drawn from the tabulated values of brass which we measured during the…
A: Here graph is between temperature and distance
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- at the temperature T=0 C, an aluminum ring has a circumference C=15cm whereas an iron cylinder has a circumference c= 15.05cm. what is the minimum common temperature we need to raise both metals to so that the cylinder can pass through the ring? (use for beta Al = 24*10-6 C-1 and beta Fe = 11*10-6 C-1 )The active element of a certain laser is made of a glass rod 30.0 cm long and 1.50 cm in diameter. Assume the average coefficient of linear expansion of the glass is 9.00 × 10–6 (°C)–1. If the temperature of the rod increases by 65.0°C, what is the increase in (a) its length, (b) its diameter, and (c) its volume?You just copied the same answer from Chegg but that one is incorrect... so far these are the results i got but i also think they're not correct. 4(a) The power radiated by the tank can be expressed in the following formula: P = εσA(Tin4 – Tout4) Where, ε = 0.76 σ = 5.67 x 10^-8 W/m2K^4 A = 2.8 m^2 T(Tin^4 – Tout^4) = (58 + 273.15 = 331.15 K)^4 – (19 + 273.15 = 292.15 K)^4 = 4740486867.42 K So Pnet= 0.76 * 5.67 × 10^-8 * 2.9 * 4740486867.42 Pnet = 592.4 W or 0.59 kW 4(b) The power lost through the insulating layer can be calculated using the following formula: Ploss = kA Ttank−Ts / l where Ploss is the power lost through the insulating layer, k is the thermal conductivity of the rock mineral wool, A is the surface area of the tank, Ttank is the temperature of the tank, Ts is the temperature of the surroundings, and l is the thickness of the insulating layer. k = 0.032 A = 2.9 m^2 Ttank = 58 °C Ts = 19°C l= 0.115 m Ploss = 0.032 * 2.9 * 58−19/115 Ploss = 31.47 W…
- The barium-yttrium ceramic compound used to demonstrate superconductivity will work only if supercooled to a temperature of 125 K. What is the equivalent temperature a) in °C? b) in °F?A walrus transfers energy by conduction through its blubber at the rate of 150 W when immersed in −1.00ºC water. The walrus’s internal core temperature is 37.0ºC , and it has a surface area of 2.00 m2 . What is the average thickness of its blubber, which has the conductivity of fattytissues without blood?A cube of solid aluminum (beta=0.000072 per Kelvin) has a volume of 1.00 m^3 at 20 degrees Celsius. What temperature change is required to produce a 100-cm^3 increase in the volume of the cube?
- The emissivity of the human skin is 97.0 percent. Use 35.0 °C for the skin temperature and approximate the human body by a rectangular block with a height of 1.77 m, a width of 33.0 cm and a length of 29.5 cm. 1. Calculate the power emitted by the human body. 2. What is the wavelength of the peak in the spectral distribution for this temperature? 3. Fortunately our environment radiates too. The human body absorbs this radiation with an absorbance of 97.0 percent, so we don't lose our internal energy so quickly. How much power do we absorb when we are in a room where the temperature is 26.0 °C? 4. How much energy does our body lose in one second? Please answer all four partsThe active element of a certain laser is made of a glass rod 28 cm long and 2.3 cm in diameter. Assume the average coefficient of linear expansion of the glass is equal to 9x10^ -6C^-1 If the temperature of the rod increases by 14, what is the increase in its volume? Express your answer in cm^3?Find the theoretical Debye temperature of copper (Cu) if the speed of soundin copper is 3901 m/s and its density and atomic mass is 8960 kg/m3 and0.06355 kg/mol, respectively.
- An incandescent light bulb has a tungsten filament that is heated to a temperature of 3.20 × 103 K when an electric current passes through it. If the surface area of the filament is approximately 1.00 × 10−4 m2 and it has an emissivity of 0.360, what is the power radiated by the bulb?The Stefan–Boltzmann constant (σ) is 5.670 × 10−8 W/(m2·K4).A 0.3-cm-thick, 12-cm-high, and 18-cm-long circuit board houses 80 closely spaced logic chips on one side, each dissipating 0.06 W. The board is impregnated with copper fillings and has an effective thermal conductivity of 16 W/m·K. All the heat generated in the chips is conducted across the circuit board and is dissipated from the back side of the board to the ambient air. Determine the temperature difference between the two sides of the circuit board.Full solution to whole qn (ans are a)1.00×10^4J b)1.00kW)