We want to find the 98th term of the arithmetic sequence with first term 29 and 10th term 92. We will use the fact that the nth term of an arithmetic progression is given by an = a₁ + (n-1)d where a, is the -Select--- We first need to find the common difference d. Since a₁ = gives the following. 92 = 92 = = 9d term and d is the common d = +(-1)d +9d -Select--- between successive terms. and a 10 the formula above with n = 10

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter12: Sequences, Series And Binomial Theorem
Section: Chapter Questions
Problem 327PT: Find the twenty-third term of an arithmetic sequence whose seventh term is 11 and common difference...
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We want to find the 98th term of the arithmetic sequence with first term 29 and 10th term 92. We will use the fact that the
nth term of an arithmetic progression is given by
an = a₁ + (n - 1)d
where a₁ is the ---Select---
We first need to find the common difference d. Since a₁ =
gives the following.
1)d
92 =
92 =
= 9d
term and d is the common ---Select---between successive terms.
d =
+
+ 9d
and a 10
=
, the formula above with n = 10
Transcribed Image Text:We want to find the 98th term of the arithmetic sequence with first term 29 and 10th term 92. We will use the fact that the nth term of an arithmetic progression is given by an = a₁ + (n - 1)d where a₁ is the ---Select--- We first need to find the common difference d. Since a₁ = gives the following. 1)d 92 = 92 = = 9d term and d is the common ---Select---between successive terms. d = + + 9d and a 10 = , the formula above with n = 10
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