​Weak base: 25 mL of 0.00255 M hydroxylamine HONH2 (Kb = 1.1 × 10-8) Strong acid: 0.001545 M HNO3.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter14: Acids And Bases
Section: Chapter Questions
Problem 118QRT
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​Weak base: 25 mL of 0.00255 M hydroxylamine HONH2 (Kb = 1.1 × 10-8) Strong acid: 0.001545 M HNO3. Questions 1-2 were previously explained and answered. Can you explain numbers 3, 4, and 5. Answers are on the side to check if your work matches answer. ​Conditions to determine: 1. Initial pH – Answer: 8.7 2. pH at 10.12 mL of titrant added ​​​​– Answer: 6.5 3. pH at equivalence point ​​​​​– Answer: 4.5 4. pH 1 mL of titrant added after the equivalence point​​– Answer: 4.4 5. pH 15 mL of titrant added after the equivalence point​– Answer: 3.5
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