Weight (kg) Mean 59 Standard Error 1.713261714 Median 57 Mode 50 Standard Deviation 11.61990629 Sample Variance 135.0222222 Kurtosis -0.656342029 Skewness 0.379370791 Range 45 Minimum 38 Maximum 83 Sum 2714 Count 46 Confidence Level(95.0%) 3.450686224 Q1 50 Q3 67
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Provide a Descriptive interpretation based on the given data; use an APA format as much as possible.
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- Female Height: Sample Size - 44, Sample Mean- 164.4 cm, Sample Variance- 83.4 cm2, Sample standard deviation- 9.1 cm Construct and interpret a 90% confi dence interval for the average height of femalesActive management of labor (AML) is a group of interventions designed to help reduce the length of labor and the rate of cesarean deliveries. Physicians from the Department of Obstetrics and Gynecology at the University of New Mexico Health Sciences Center were interested in determining whether AML would also translate into reduced cost of delivery. According to their study, 300 AML deliveries had sample mean cost of $2,480 and sample standard deviation of $766. At the time of the study, the average cost of having a baby in a U.S. hospital was $2,528. a. The value of the test statistic and the p-value is b. If five percent significance level is used the rejection region is c. At 5% significance level we can conclude that mean AML delivery costThe accuracy of a coin-counter machine is gauged to accept nickels with a mean diameter of millimeters 21.21 mm. A sample of 45 nickles was drawn from a reported defective coin-counter machine located near a school. The sample had a sample mean of 21.214 mm and sample standard deviation 0.009 mm. Test the claim that the mean nickel diameter accepted by this coin-counter machine is greater than 21.21 mm. Test at the 0.05 significance level. (a) Identify the correct alternative hypothesis HaHa: μ>21.21μ>21.21 μ=21.21μ=21.21 μ<21.21μ<21.21 Give all answers correct to 4 decimal places. (b) The test statistic value is: (c) Using the Traditional method, the critical value is: (d) Based on your answers above, do you: Reject H0H0 Fail to reject H0H0 (e) Explain your choice. (f) Based on your work above, choose one of the following conclusions of your test: The sample data supports the claim There is not sufficient evidence to warrant rejection of the claim There is not sufficient…
- Active management of labor (AML) is a group of interventions designed to help reduce the length of labor and the rate of cesarean deliveries. Physicians from the Department of Obstetrics and Gynecology at the University of New Mexico Health Sciences Center were interested in determining whether AML would also translate into reduced cost of delivery. According to their study, 500 AML deliveries had a sample mean cost of $2,480 dollars with a sample standard deviation of $766. The average cost of all AML deliveries is to be estimated with 90% confidence interval. a. The t − or z −value that should be used to construct this interval is b. The margin of error is equal to c. The confidence interval isThe accuracy of a coin-counter machine is gauged to accept nickels with a mean diameter of millimeters 21.21 mm. A sample of 35 nickles was drawn from a reported defective coin-counter machine located near a school. The sample had a sample mean of 21.211 mm and sample standard deviation 0.01 mm. Test the claim that the mean nickel diameter accepted by this coin-counter machine is greater than 21.21 mm. Test at the 0.05 significance level. (a) Identify the correct alternative hypothesis HaHa: μ=21.21μ=21.21 μ>21.21μ>21.21 μ<21.21μ<21.21 Give all answers correct to 4 decimal places. (b) The test statistic value is: (c) Using the Traditional method, the critical value is: (d) Based on your answers above, do you: Reject H0H0 Fail to reject H0H0 (e) Explain your choice in the box below. (f) Based on your work above, choose one of the following conclusions of your test: There is sufficient evidence to warrant rejection of the claim There is not sufficient evidence…A clothing retailer is interested in the average waist size of men. A sample is taken with the results given below. Column1 Mean 41.39 Standard Deviation 1.033 Median 41 Mode 41 Standard Deviation 5.466 Sample Variance 29.88 Kurtosis 0.474 Skewness 0.608 Range 21 Minimum 32 Maximum 53 Sum 1159 Count 60 Confidence level (95.0%) 2.119 What is the sample statistic? What is the point estimate for the average waist size? What is the level of confidence as a decimal? What is the margin of error? What is the confidence interval?
- The accuracy of a coin-counter machine is gauged to accept nickels with a mean diameter of millimeters 21.21 mm. A sample of 36 nickles was drawn from a reported defective coin-counter machine located near a school. The sample had a sample mean of 21.213 mm and sample standard deviation 0.007 mm. Test the claim that the mean nickel diameter accepted by this coin-counter machine is greater than 21.21 mm. Test at the 0.01 significance level. (a) Identify the correct alternative hypothesis Ha : μ<21.21 μ=21.21 μ>21.21 Give all answers correct to 4 decimal places. (b) The test statistic value is: (c) Using the Traditional method, the critical value is: (d) Based on your asnwers above, do you: (i) Reject H0 (ii) Fail to reject H0The average baptismal cost includes 50 guests. A random sample of 32 baptismalduring the past year in the National Capital Region had a mean of 53 guests and astandard deviation of 10 is there sufficient evidence at the 0.05 level of significancethat the average number of guests differs from the national average.The accuracy of a coin-counter machine is gauged to accept nickels with a mean diameter of millimeters 21.21 mm. A sample of 47 nickles was drawn from a reported defective coin-counter machine located near a school. The sample had a sample mean of 21.214 mm and sample standard deviation 0.01 mm.Test the claim that the mean nickel diameter accepted by this coin-counter machine is greater than 21.21 mm. Test at the 0.1 significance level.(a) Identify the correct alternative hypothesis HaHa: μ<21.21μ<21.21 μ=21.21μ=21.21 μ>21.21μ>21.21 Give all answers correct to 4 decimal places.(b) The test statistic value is: (c) Using the Traditional method, the critical value is: Based on your answers above, do you: Fail to reject H0H0 Reject H0
- In a camping group, two groups of campers were considered and their scores were recorded. We are using a 0.05 significance level to test the claim that students of group 2 have a higher mean than those of group 1. Group 1 n = 40, sample mean = 78.40, sample standard deviation = 12.87 Group 2 n = 34, sample mean = 81.62, sample standard deviation = 22.09 what is error and CIType I error: Washers used in a certain application are supposed to have a thickness of 2 millimeters. A quality control engineer measures the thicknesses for a sample of washers and tests H0: μ = 2 versus H1: μ ≠ 2. a. If a Type I error is made, what conclusion will be drawn regarding the mean washer thickness?The accuracy of a coin-counter machine is gauged to accept nickels with a mean diameter of millimeters 21.21 mm. A sample of 36 nickles was drawn from a reported defective coin-counter machine located near a school. The sample had a sample mean of 21.215 mm and sample standard deviation 0.011 mm.Test the claim that the mean nickel diameter accepted by this coin-counter machine is greater than 21.21 mm. Test at the 0.1 significance level.(a) Identify the correct alternative hypothesis HaHa: μ<21.21μ<21.21 μ>21.21μ>21.21 μ=21.21μ=21.21 Give all answers correct to 4 decimal places.(b) The test statistic value is: (c) Using the Traditional method, the critical value is: (d) Based on your answers above, do you: Fail to reject H0H0 Reject H0H0 (e) Explain your choice in the box below.(f) Based on your work above, choose one of the following conclusions of your test: There is not sufficient evidence to warrant rejection of the claim The sample data supports the claim…