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- Answer the problem by choosing one of the eight labeled acceleration vectors or selecting option I: a→ = 0→. At this instant, the particle has steady speed and is curving to the right. What is the direction of its acceleration?A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by theta = (5t^2) rad, where t is in seconds. Determine the magnitude of the particle’s acceleration when theta = 30°. The particle starts from rest when u = 0°.A child running in a field has the following position and velocity at time t=0: x = 1.5 m. v= -2.0 m. Vx =-3.5 m/s, vy = 1.0 m/s At time t = 2.5 s, it has the following position and velocitv: x = -1.0 m, y = 1.5 m 08. Vx = -0.50 m/s, Vy = 2.0 m/s Using this information, find the magnitude and direction of the child's…
- A particle leaves the origin with an initial velocity v→=(2.33î) m/s and a constant acceleration a→=(-4.30î-2.65ĵ) m/s2. When the particle reaches its maximum x coordinate, what are (a) its velocity, (b) its position vector?A clown juggle balls while doing other activities. In one act, she throws a ball vertically upward, and while it is in the air, she runs to and from a table 5.5 m away at constant speed of 2.5 m/s, returning just in time to catch the falling ball. With what minimum initial speed must she throw the ball upward to accomplish the act?Answer the problem by choosing one of the eight labeled acceleration vectors or selecting option I: a→ = 0→. At this instant, the particle is speeding up and curving upward. What is the direction of its acceleration?
- You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle ? with respect to the horizontal. Let the building be 54.0 m tall, the initial horizontal velocity be 8.60 m/s, and the initial vertical velocity be 12.5 m/s. Choose your coordinates such that the positive y-axis is upward, and the x-axis is to the right, and the origin is at the point where the ball is released. (a) With these choices, find the ball's maximum height above the ground and the time it takes to reach the maximum height. maximum height above ground m time to reach maximum height s (b) Repeat your calculations choosing the origin at the base of the building. maximum height above ground m time to reach maximum height sA particle starts from the origin at t=0, with an initial velocity having an x component of 20m/s and a y component of -15m/s. The particle moves in the xy plane with an x component of acceleration only, given by Ax =4.0 m/s^2 Determine the components of the velocity vector at anytime and the total velocity vector at any time . Calculate the velocity and speed of the particle at t=5.0s.At t=0, a ball is thrown with an initial velocity of magnitude 15ms-1 at 75° to the horizontal (upwards). Which way is the ball moving at this time? What is the magnitude of the horizontal component of velocity at t=2.0s?