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What are the concentrations of each species in the reaction when you reach equilibrium of a 0.15 M solution of HCN?
HCN(aq)⇌H+(aq)+CN-(aq)
Kc = 4.9×10−10
Given :-
Initial concentration of HCN = 0.15 M
Kc = 4.9 × 10-10
To calculate :- equilibrium concentration of all species. [HCN], [H+],[CN-]
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