Ammonia, NH3, is a base and will readily accept a proton in accordance with the following reaction: NH3(aq) + H2O <-> NH4+ + OH- Calculate the equilibrium constant for this reaction (the reaction goes from left to right) at 25 ºC. ∆G0NH3(ag) = -26.6 kJ/mol ∆G0H2O = -237.1 kJ/mol ∆G0NH4+ = -79.3 kJ/mol ∆G0OH- = -157.2 kJ/mol
Ammonia, NH3, is a base and will readily accept a proton in accordance with the following reaction: NH3(aq) + H2O <-> NH4+ + OH- Calculate the equilibrium constant for this reaction (the reaction goes from left to right) at 25 ºC. ∆G0NH3(ag) = -26.6 kJ/mol ∆G0H2O = -237.1 kJ/mol ∆G0NH4+ = -79.3 kJ/mol ∆G0OH- = -157.2 kJ/mol
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 38P
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Ammonia, NH3, is a base and will readily accept a proton in accordance with the following reaction:
NH3(aq) + H2O <-> NH4+ + OH-
Calculate the equilibrium constant for this reaction (the reaction goes from left to right) at 25 ºC.
∆G0NH3(ag) = -26.6 kJ/mol
∆G0H2O = -237.1 kJ/mol
∆G0NH4+ = -79.3 kJ/mol
∆G0OH- = -157.2 kJ/mol
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