Question

Asked Oct 5, 2019

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What is the axis of symmetry for the equatiin: f(x)=2(x+1)^2+1

Step 1

f(x)=2(x+1)^{2}+1

As a first step, we need to compare this equation with the equation of a parabola in standard vertex form f(x) = ( x - h) ^{2} + k.

On visual comparision, we find that

h = - 1, k = 1

Step 2

Hence, equation of the axis of the symmetery will be: x...

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