What is the calculated value of the cell potential at 298 K for an electrochemical cell with the following reaction, when the Pb²+ concentration is 1.69 x 10-4 M and the Mg²+ concentration is 1.43 M? Pb²+ (aq) + Mg(s) → Pb(s) + Mg²+ (aq) Pb2+ (aq) + 2e → Pb(s) Ered = -0.126 V Mg2+ (aq) + 2e Mg(s) Fred = -2.370 V → Ecell = The cell reaction as written above is spontaneous for the concentrations given: O true Ofalse V
What is the calculated value of the cell potential at 298 K for an electrochemical cell with the following reaction, when the Pb²+ concentration is 1.69 x 10-4 M and the Mg²+ concentration is 1.43 M? Pb²+ (aq) + Mg(s) → Pb(s) + Mg²+ (aq) Pb2+ (aq) + 2e → Pb(s) Ered = -0.126 V Mg2+ (aq) + 2e Mg(s) Fred = -2.370 V → Ecell = The cell reaction as written above is spontaneous for the concentrations given: O true Ofalse V
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter20: Electrochemistry
Section20.1: Voltaic Cells
Problem 13SSC
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Transcribed Image Text:What is the calculated value of the cell potential at 298 K for an electrochemical cell with the following reaction, when the Pb²+ concentration is 1.69 × 10-4 M and the Mg²+
concentration is 1.43 M?
Pb²+ (aq) + Mg(s) → Pb(s) + Mg²+ (aq)
(aq) + 2e → Pb(s) Fred = -0.126 V
Mg(s) Fred
Eº
= -2.370 V
Pb²+
Mg2+ (aq) + 2e
Ecell =
The cell reaction as written above is spontaneous for the concentrations given:
O true
Ofalse
V
Transcribed Image Text:What is the calculated value of the cell potential at 298 K for an electrochemical cell with the following reaction, when the Pb²+ concentration is 1.35 M and the A1³+ concentration is
9.35 x 10-4 M?
3Pb²+ (aq) + 2Al(s)
Pb²+ (aq) + 2e →
= -0.126 V
A1³+ (aq) + 3e → Al(s) Ee = -1.660 V
red
3Pb(s) + 2A1³+ (aq)
V
Pb(s) E
red
Ecell =
The cell reaction as written above is spontaneous for the concentrations given:
O true
Ofalse
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