What is the curent read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1, R2, and R3 respectively. Input E for the emf E, Use context clues to figure out if you need to input a numerical value, variable, word, etc. AN numerical answers should be in three significant figures. R| R2 R3 First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Piease note that the curent is in miliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the ourrents across each resistor: |=l1 +12+l3 Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Req =/R1 + 1/R2 +1/ Thus. Reg=

What is the curent read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1, R2, and R3 respectively. Input E for the emf E, Use context clues to figure out if you need to input a numerical value, variable, word, etc. AN numerical answers should be in three significant figures. R| R2 R3 First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Piease note that the curent is in miliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the ourrents across each resistor: |=l1 +12+l3 Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Req =/R1 + 1/R2 +1/ Thus. Reg=

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 75A

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Similar questions

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