What is the final value of S in the following program (type Number only): * S=0 Do 50 i=1,7 S=S+i If (i == 4) then Goto 60 else end if 50 Continue 60 Write (*,*) S
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Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
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- Void Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program isRun the following code and answer the questions. #include <stdio.h> int main(void) { int a; char *s; int v0 = 9, v1 = 0, v2 = 0, v3 = 0; printf("Exercise 1:\n====================\n"); switch(v0) { case 0: printf("Good day\n"); break; case 1: printf("Hey There!\n"); break; case 2: printf("No Name\n"); break; case 3: printf("Yes Please\n"); break; case 4: printf("Go "); case 5: printf("Vamos!\n"); default: printf(" "); break; } for(v1; v1<v2; v1=v1+v1) { printf("Vamos "); } printf("\n"); if (v2 == 6) { s = "Go"; } if(v3 != 0) { printf("%s VAMOS!\n",s); } return 0; } What is the output of the program? Please explain why using the variables v0, v1, v2, and v3.…A polynomial is given by f=(8.5×v×v)−(7.0×v)+3.5. Declare double variables v and f. Then, read v from input and compute f using the polynomial. Ex: If the input is 1.0, then the output is: 5.000 #include <iomanip>#include <cmath>#include <iostream>using namespace std; int main() { /* Your code goes here */ cout << fixed << setprecision(3) << f << endl; return 0;}
- 3. B) What is the value of num when the following code snippet runs successfully? int num = 100; if (num < 100) { if (num < 50) { num -= 5; } else { num -= 10; } } else { if (num > 150) { num += 5; } else { num += 10; } } C) A store provides 10 percent discount on all items with a price of at least $100. No discount is otherwise applicable. Assume that two variables are declared, discount and price. Write the code segment that does the job.analyze the following code .Which of the following is not correct? if (number>0) cout<<number; cout<<number; A. Number ls always printed out twice. B. Number is printed ont once if mumber is zero C. Numbvers printed out once if number is negative. D.Number is printed out twice onty if mumber is positive.Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the gas cost for 20 miles, 75 miles, and 500 miles. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 20.0 3.1599 the output is: 3.16 11.85 79.00
- What does the following code segment display? for(f=0; f<3; ++f); write ("{0} ", f); a. 0 b. nothing c. 3 d. 0 1 2By default, which one of the following types of values will be thrown when the below function is executed?def abstractAdd(a,b,c):print(a+b+c) Choose an answer A None B bool C str D intWhat will be the value of ans after the following code has been executed? int x = 90, y = 55, ans = 10; if ( x == y); ans *= 2; 1. 10 2. 145 3. 20 4. None of these
- With the following variables declared and initialized... double dVar1 = 25.0, dVar2 = 2.5; int iVar1 = 15, iVar2 = 30; String s1 = "hi", s2 = "there"; ...show what is printed for at least 5 of the 6 following statements: a) System.out.println( (iVar1/iVar2) > (iVar2%iVar1) ); b) System.out.println( s2.length() + s1 + dVar2 ); c) System.out.println( (int) (dVar2 / s1.length()) ); d) System.out.println( s2 + " is " + iVar2 * dVar2 );// This program gets student names continuously until XXX is entered. Then, for each student, quiz scores are entered until O is entered. Then the student's name and total are displayed. start Declarations string name num score string QUIT = - "XXX" num OUIT SCORE = 0 num total (housekeeping () output "Please enter name or XXX to quit" input name housekeeping O return name <> QUIT? No Yes detailLoop( (endofjob () endofJob ( stop output "Job complete" (return what needs to be added and fixed? Debugging 5-04Re- write the following program by using switch statement int main() { int code; Cout<<"enter code(a or A, bo B"; Cin>>Code; If ( code == 'a' && code =='A'} cout < < ''Sometimes you win" cout<< " Sometimes you learn"; else if (code =='b' &&& code== 'B') cout < < ''Don't wait for the perfect moment"; cout<< " Take the moment and make it perfect"; else Cout<<"Wrong code entered"; Return 0;