What is the margin of error för a sample of 34 students whose average height. with 90% confidence, can be found between 47.5" and 50.5"?*

Q: In a survey, 31 people were asked how much they spent on their child's last birthday gift. The…

A: Sample size, n = 31Mean = 48Standard deviation = 8

Q: In a survey, 29 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=29mean(x¯)=47standard deviation(s)=2α=1-0.95=0.05α2=0.025Degrees of…

Q: In a survey, 19 people were asked how much they spent on their child's last birthday gift. The…

A: It is given that, Mean = 35 Standard deviation = 9 Same size = 19

Q: In a survey, 11 people were asked how much they spent on their child's last birthday gift. The…

A: We have to find margin of error

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: As we may all know, adults use credit cards for all sorts of reasons. A survey found that 66% of…

A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

A: Given: n=15,σ=$10,α=1-0.9=0.1

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The res…

A: The summary of statistics is, x¯=31,s=4,n=26 The degree of freedom is, df=n-1   =26-1   =25 Critical…

Q: A uSa today/CNN/Gallup survey of 369 working parents found 200 who said they spendtoo little time…

A:

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: Given data, n=10 x=35 s=4 c=99%

Q: In a survey, 24 people were asked how much they spent on their child's last birthday gift. The…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: what would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation…

A: It is given that mean and standard deviation are 51 and 12, respectively.

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A 97% confidence interval for proportion is found to be (.221, .623).  The Margin of Error is?

A: Given : A 97% confidence interval for proportion is found to be (0.221, 0.623)

Q: In a survey, 31 people were asked how much they spent on their child's last birthday gift. The…

A: Given: σ = $ 2  n = 31

Q: A study at Harvard found that 44% of their students binge drink. You are at Princeton doing a…

A:

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A: Given  The results were roughly bell-shaped with a mean of $37 and standard deviation of $3 Sample…

Q: How large a sample is necessary to estimate the true proportion of unmarried Canadians aged 25-29…

A: Given data: Margin of error  = 5% = 0.05 Confidence level  = 0.90 To find: Sample size (n) = ?

Q: In a survey, 19 people were asked how much they spent on their child's last birthday gift. The…

A: From the given information, the sample mean is $49, the sample standard deviation is $3 and the…

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: Given, Sample size, n = 13 Sample mean = 44 Sample standard deviation, s = 10 Confidence level = 80%…

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = $ 44, standard deviation (s) = $ 10, sample size (n) = 30…

Q: In a survey, 22 people were asked how much they spent on their child's last birthday gift. The…

A: Solution: From the given information, confidence level is 0.80, σ=$10 and n=22.

Q: In a survey, 15 people were asked how much they spent on their child's last birthday gift. The…

A: Solution: From the given information, S=2 and n=15. The confidence level is 0.98.

Q: In a survey, 16 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In 2010, the proportion of Texans without health insurance was 0.11. To update this information a…

A:

Q: In a survey, 11 people were asked how much they spent on their child's last birthday gift. The…

A: The summary of statistics is,

Q: In a survey, 28 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: It is estimated that 60 percent of U.S. households now get cable television. You would like to…

A: Solution: From the given information, confidence level is 0.95, p=0.60 and E=0.05.

Q: What is the margin of error for a sample of 34 students whose average height, with 90% confidence,…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 27 people were asked how much they spent on their child's last birthday gift. The…

A: The mean is $36 and the standard deviation is $6.

Q: In a survey, 17 people were asked how much they spent on their child's last birthday gift. The…

A: Given that: Sample size=n=17 Sample mean=x¯=41Standard deviation=s=999% confidence level, i.e,…

Q: In a survey, 11 people were asked how much they spent on their child's last birthday gift. The…

A: Since population standard deviation is unknown, use t-distribution to find t-critical value. Find…

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 29 people were asked how much they spent on their child's last birthday gift. The…

A: Given that, n=29 mean=$50 S.D=$8

Q: In a survey, 14 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 12 people were asked how much they spent on their child's last birthday gift. The…

A: Given: Sample size = 12 Sample mean  = $45 Sample standard deviation = $8 To find: Margin of error…

Q: A survey of 2500 teen-agers noted that 60% of them are extensive internet users. With 90% confidence…

A:

Q: An online poll of 810 adults found that 53% of the respondents think critical thinking should be…

A: Given info: An online poll of 810 adults found that 53% of the respondents think critical thinking…

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A: Given: n=25x¯=35s=2C.I.=99% Formula used: Since, here sample size is less than 30, t-distribution is…

Q: In a survey, 19 people were asked how much they spent on their child's last birthday gift. The…

A: The summary of the statistics is, The degree of freedom is, df=n-1   =19-1   =18 Critical value: By…

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 18 people were asked how much they spent on their child's last birthday gift. The…

A: Mean = 34 Standard deviation = 3 Sample size, n = 18

Q: . What sample size would be required to estimate the proportion of all hospital referrals to the…

A: Sample Size: The formula for the sample size is as follows: Here, zα/2 is the critical value at 95%…

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A: Mean = 38 Standard deviation = 8 Sample size = 26 99% confidence level

Q: In a survey, 20 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: If the variance of the water temperature in a lake is 28 degrees. How many days (sample size n)…

A: The formula for finding the sample size is,