What is the maximum mass of S8 that can be produced by combining 93.0 g of each reactant? 8SO2+16H2S⟶3S8+16H2O STRATEGY: Convert 93.0 g SO2 to moles, then find the corresponding amount of S8. Convert 93.0 g H2S to moles, then find the corresponding amount of S8. Identify the limiting reactant and calculate the mass of S8 produced. Step 1: 93.0 g SO2 and excess H2S produce 0.544 mol S8. Step 2: 93.0 g H2S and excess SO2 produce 0.512 mol. Step 3: When 93.0 g SO2 and 93.0 g H2S are mixed, how much S8 forms? How much S8 forms? -0.544 mol S8 -0.544+0.512 mol S8 -0.512 mol S8   which is equal to: _________ g S8

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Chapter3: Stoichiometry
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Problem 7RQ: Consider the hypothetical reaction between A2 and AB pictured below. What is the balanced equation?...
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What is the maximum mass of S8 that can be produced by combining 93.0 g of each reactant?

8SO2+16H2S⟶3S8+16H2O

STRATEGY:

  1. Convert 93.0 g SO2 to moles, then find the corresponding amount of S8.
  2. Convert 93.0 g H2S to moles, then find the corresponding amount of S8.
  3. Identify the limiting reactant and calculate the mass of S8 produced.

Step 1: 93.0 g SO2 and excess H2S produce 0.544 mol S8.

Step 2: 93.0 g H2S and excess SO2 produce 0.512 mol.

Step 3: When 93.0 g SO2 and 93.0 g H2S are mixed, how much S8 forms?

How much S8 forms?
-0.544 mol S8
-0.544+0.512 mol S8
-0.512 mol S8
 
which is equal to: _________ g S8
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