What is the maximum yield of water (MW = 18.0 g/mol) when 2.80 moles of N2H4 gas are reacted with 11.7 moles of O2 gas?
2 N2H4(g) + 7 O2(g) → 2 N2O5(g) + 4 H2O(g)

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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
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What is the maximum yield of water (MW = 18.0 g/mol) when 2.80 moles of N2H4 gas are reacted with 11.7 moles of O2 gas?
2 N2H4(g) + 7 O2(g) → 2 N2O5(g) + 4 H2O(g)

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