What is the minimum diameter of a solid steel shaft that will not twist through more than 6° in a 15-m length when subjected to a torque of 8 kN·m? Use G = 83 GPa. How can you make stress of the element (rho=55mm) in question be equal to 45MPa?

What is the minimum diameter of a solid steel shaft that will not twist through more than 6° in a 15-m length when subjected to a torque of 8 kN·m? Use G = 83 GPa. How can you make stress of the element (rho=55mm) in question be equal to 45MPa?

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.7.10P: What is the maximum power that can be delivered by a hollow propeller shaft (outside diameter 50 mm,...

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

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What is the minimum diameter of a solid steel shaft that will not twist through more than 6° in a 15-m length when
subjected to a torque of 8 kN·m? Use G = 83 GPa.
How can you make stress of the element (rho=55mm) in question be equal to 45MPa?

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