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What is the order for x?
![time [X]t
(s)
(M)
0.0
234.00
10.0 222.59
30.0 201.41
70.0
164.90
150.0 110.53
170.0 100.02
200.0 86.08
300.0 52.21
400.0 31.67
500.0 19.21
600.0 11.65](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F291cba00-a830-43f3-8558-42921e09aec8%2F6c7c726d-7476-4797-b1d6-42b66034f1ca%2Fqo14gpg_processed.jpeg&w=3840&q=75)
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- Determine the average rate of change of BB from ?=0 s�=0 s to ?=392 s.�=392 s. A⟶2BA⟶2B Time (s) Concentration of A (M) 0 0.7300.730 196196 0.4450.445 392392 0.160The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 Use the following grids to plot three separate graphs of [C12H22O11], ln[C12H22O11], and 1/[C12H22O11] against time to determine the reaction order. (a)Write the rate law expression in its general form (water should not be included). (b)Determine the rate constant with units. (c)Determine the half-life. (d)If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed?Use this data to determine the value of the rate constant. Ex # [A] (M) [B] (M) Rate (M/hr) 1 .240 .120 2.00 2 .120 .120 .500 3 .240 .0600 1.00 Question 4 options: 289 per hour 579 per hour 8.3 per hour 0.0144 per hour 69.4 per hour .00346 per hour 0.060 per hour 0.0173 per hour 17 per hour 0.12 per hour
- Sucrose (C12H22O11)(C12H22O11), which is commonly known as table sugar, reacts in dilute acid solutions to form two simpler sugars, glucose and fructose, both of which have the formula C6H12O6C6H12O6. At 23 ∘C∘C and in 0.5 M HClM HCl, the following data were obtained for the disappearance of sucrose: Time (min)(min) C12H22O11(M)C12H22O11(M) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 What is the rate constant?A chemistry grad student measures the performance of the new pump in his lab. The result is: Z=19.1 kPa·mm3·s-1 conver Z to mJ·s-1Determine the average rate of change of BB from ?=0 st=0 s to ?=272 s.t=272 s. A⟶2BA⟶2B Time (s) Concentration of A (M) 0 0.7300.730 136136 0.4450.445 272272 0.1600.160 rateB= __________M/s
- 1. Ozone reacts with sulfur dioxide to form sulfur trioxide and molecular oxygen, as shown here.O3 (g) + SO2 (g) → O2 (g) + SO3 (g)In one study of this reaction, the amount of ozone present was measured and recorded at several points during the course of the reaction. These data are presented in the accompanying table.Time (s) Moles O30 0.300100 0.226200 0.170400 0.097600 0.055800 0.031Use the data in the table to answer the following questions.a. What is the average rate of consumption of O3 over the first 100 seconds of the reaction?b. What is the average rate of consumption of O3 during the period from 400 seconds to 800 seconds?c. If the average rate of consumption of O3 is 0.00024 mol/s during the period from 400 seconds to 500 seconds, how much ozone is present at 500 seconds?d. Use the blank graph provided here to plot the amount of ozone as a function of time.e. Use the graph that you constructed to estimate the average rate of consumption of O3 during the period from 50…For the fictitious reaction: AB → A + B Some data was collected measuring the [AB] at certain time intervals. This data was then graphed as described below. A graph of 1/[AB] versus time (s) gives a straight line with the equation: y = 0.0052x + 0.1135 and a R2 = 0.9995. A graph of ln[AB] versus time (s) gives a straight line with the equation: y = -0.0068x + 1.725 and a R2 = 0.8925. Assume the data doesn't fit a zero order reaction. The rate law is: Rate = k[AB]2 Find: What is the value of the rate constant for the given reaction? Select one: a. k = 0.0157 Ms-1 b. k = 0.0052 M-1s-1 c. k = 0.0068 s-1 d. There is no way to determine the value of the rate constant from the given information.The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (A) If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed?
- Please send me the question in 20 minutes it's very urgent plz only question number 1Use the information given here to answer both questions (4 and 5). For the fictitious reaction: AB → A + B Some data was collected measuring the [AB] at certain time intervals. This data was then graphed as described below. A graph of 1/[AB] versus time (s) gives a straight line with the equation: y = 0.0052x + 0.1135 and a R2 = 0.9995. A graph of ln[AB] versus time (s) gives a straight line with the equation: y = -0.0068x + 1.725 and a R2 = 0.8925. Assume the data doesn't fit a zero order reaction. What is the rate law for this reaction? Select one: a. Rate = k[AB]2 b. Rate = k[A][B] c. Rate = k[AB] d. Rate = k Using the data from the previous question. What is the value of the rate constant for the given reaction? Select one: a. k = 0.0052 M-1s-1 b. k = 0.0157 Ms-1 c. k = 0.0068 s-1 d. There is no way to determine the value of the rate constant from the given information.1. The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (a)If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed? 2. Methyl isomerizes to acetonitrile, CH3NC(g) → CH3CN(g) at 215°C. The following data were collected during the process: Time (sec) [CH3NC] (mol/L) 2000 0.0110 5000 0.0059 8000 0.0031 12000 0.0014 15000 0.0007 2. (a)Assuming the process continues, what concentration of methyl isonitrile would we expect after 5.00 h?