What is the output of the following code? #include int main(){ int b = LAST_FOUR_DIGIT_OF_YOUR_STUDENT_ID % 11; int a[5] = {b+1, b+2, b+3, b+4, b+5}; int *p1,t,u,v,w; p1=a3; t= (*p1)++; u= *p1; v = *++p1; w = *(++p1); printf("%d %d %d %d", t, u, v, w);

What is the output of the following code? #include int main(){ int b = LAST_FOUR_DIGIT_OF_YOUR_STUDENT_ID % 11; int a[5] = {b+1, b+2, b+3, b+4, b+5}; int p1,t,u,v,w; p1=a3; t= (p1)++; u= p1; v = ++p1; w = *(++p1); printf("%d %d %d %d", t, u, v, w);

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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my js code: // Define arrays for income and expenses let income = [ { name: 'Salary', amount: 4000, recurring: true }, { name: 'Freelance Work', amount: 1000, recurring: false }, { name: 'Gift', amount: 50, recurring: false }, { name: 'Bonus', amount: 500, recurring: true }, { name: 'Investment Income', amount: 200, recurring: true } ]; let expenses = [ { name: 'Rent', amount: 1500, recurring: true }, { name: 'Groceries', amount: 350, recurring: true }, { name: 'Utilities', amount: 200, recurring: true }, { name: 'Transportation', amount: 100, recurring: true }, { name: 'Entertainment', amount: 50, recurring: false } ]; // Function to display the income list function displayIncome() { let table = document.createElement('table'); let totalIncome = 0; for (let i = 0; i < income.length; i++) { let row = document.createElement('tr'); let nameCell = document.createElement('td'); nameCell.textContent = income[i].name; let amountCell = document.createElement('td');…
Hello.. i hope you are well. please code this for me in java and follow the instructions mentioned as it is Write code that uses lambdas and streams to satisfy the requirements listed below. Print a list of all employees that earn $50,000 or more:Print a list of the names (not the Employee instances) of all employees who were hired on or after Jan. 1, 2012.Print the maximum salary of all employees.Print the minimum salary of all employeesNow, print the average salary of all Female and Male employees:Finally, use the reduce() operation to find the Employee instance of the employee with the highest salary:
Can you please explain this C code beside every code on each line: #include <stdio.h> int main() { long long int level; long long int time; long long int orderTime; long long int minimumTime = 0; scanf("%d", &level); getchar(); long long int array1[level]; long long int array2[level + 1]; long long int array3[level + 1]; for(int i = 0; i < level - 1; i++) { scanf("%lld", &array1[i]); getchar(); } for(int i = 0; i < level; i++){ scanf("%lld", &array2[i]); getchar(); } for(int i = 0; i < level; i++){ scanf("%lld", &array3[i]); getchar(); } for(int i = level - 1; i >= 1; i--) { if(array3[i] > array2[i]) { time = array3[i] - array2[i]; array2[i - 1] = array2[i - 1] - time; array2[i] = array2[i] + time; orderTime =…
I need a C code of this: Implement the following functions: void createArray(int arr[],int count); /*Asks the user for the elements of the array.*/ int findFather(int arr[],int count); /*returns the largest sum possible*/ int findSon(int arr[],int count); /*returns the smallest sum possible*/ void display(int father, int son); /*displays the largest and smallest sum*/ Input 1. The size of the array Constraints The value is >= 3. 2. The values inside the array Constraints The value is within the range: <= 2147483647 and >= -2147483648 #include<stdio.h>#define SIZE 100int main(void) { int arr[SIZE]; int count; int father; int son; printf("Enter the size: "); scanf("%d",&count); createArray(arr,count); father = findFather(arr,count); son = findSon(arr,count); display(father, son); return 0;} Output should be: Enter the size: 4 Enter the values: 1 2 3 4 Father = 9, Son = 6
#include <stdio.h>#include <string.h> struct user { char user_name[10]; char bank_name[10]; int account_num[4]; int card_number[14]; int pass[4]; int balance; int wallet_num[11];}; int num_acc;int withdrawal;int deposition;char transaction;int k;int number_of_papers;int choice4; void print_array(int arr[], int size){ for (int i = 0; i < size; i++) { printf("%d", arr[i]); } printf("\n");} void print_struct(char username[], char bankname[], int accountnum[], int size3, int cardnum[], int size4, int balance){ printf("Username is %s", username); printf("\nBankname is %s\n", bankname); printf("Account number is "); print_array(accountnum, size3); printf("Cardnumber is "); print_array(cardnum, size4); printf("Balance is %d\n", balance);} void scan_array(int arr[], int size){ for (int i = 0; i < size; i++) { scanf_s("%d", &arr[i]); } } int search_name_in_array(struct user user[], int size1, char…
Q1 #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…
Following code is for 4×4 tic toc toe game covert this code in to 3×3 players. Code #include <iostream> using namespace std; class Board { char board[4][4]; public: Board() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { board[i][j]='_'; } } } void printBoard() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { cout<<board[i][j]<<'|'; } cout<<endl; } cout<<endl; } int setPosition(char choice) { while(1) { int row,column; cout<<"Please enter the row and column"<<endl; cin>>row>>column; if(board[row][column]=='_') { board[row][column]=choice; break; } else { cout<<"Position is taken"<<endl; } } } char getPosition() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { return board[i][j]; } } } int checkHorizontal(char choice) { int count; for(int i=0;i<4;i++) {…
Can you answer it according to the code below #include #define MAX_EMP 5 struct Employee { int id; int age; float salary; }; int count = 0; struct Employee emp[MAX_EMP]; void display() { printf("\n---=== EMPLOYEE DATA ===---\n"); printf("EMP ID\tEMP AGE\tEMP SALARY\n"); printf("======\t=======\t==========\n"); for(int i = 0; i < count; i++) { printf("%d\t%d\t%.2f\n", emp[i].id, emp[i].age, emp[i].salary); } } void add() { if(count == MAX_EMP) { printf("\nERROR!!! Maximum Number of Employees Reached\n"); return; } printf("\nAdding Employee ===============\n"); printf("Enter Employee ID: "); scanf("%d", &emp[count].id); printf("Enter Employee Age: "); scanf("%d", &emp[count].age); printf("Enter Employee Salary: "); scanf("%f", &emp[count].salary); count++; } void update() { int id, found = 0; float newSalary; printf("\nUpdate Employee Salary…
Analyze the following code: int[][] matrix = new int[5][5];for (int column = 0; column < matrix[4].length; column++); matrix[4][column] = 10; A. After the loop, the last row of matrix is 10, 10, 10, 10, 10. B. A syntax error, because column is not defined. C. After the loop, the last column of matrix is 10, 10, 10, 10, 10. D. After the loop, the last row of matrix is 0, 0, 0, 0, 10.
in Java please This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balanced team. (1) Prompt the user to input five pairs of numbers: A player's jersey number (0 - 99, but this is NOT enforced by the program nor tested) and the player's rating (1 - 9, not enforced like jersey numbers). Store the jersey numbers in one int array and the ratings in another int array. Output these arrays (i.e., output the roster) as shown below after inputting the data. Ex Enter player 1's jersey number: 84 Enter player 1's rating: 7 Enter player 2's jersey number: 23 Enter player 2's rating: 4 Enter player 3's jersey number: 4 Enter player 3's rating: 5 Enter player 4's jersey number: 30 Enter player 4's rating: 2 Enter player 5's jersey number: 66 Enter player 5's rating: 9 ROSTER Player 1 -- Jersey number: 84, Rating: 7 Player 2 -- Jersey number: 23, Rating: 4 . . . (2) Implement a menu of options for a user to modify the roster. Each…
Hi, I am implementing a matrox with several functions. I have pasted the error, the assignment and my code. Hopefully you can see what causes the error and how to fix it. Thank you so much. My transpose function gives an error: IndexError: list assignment index out of range self = <tests_matrix.TestsStudent testMethod=test_transpose> def test_transpose(self): self.assertEqual(str(self.a.transpose()), ' 1 4 7\n 2 5 8\n 3 6 9\n') self.assertEqual(str(self.b.transpose()), ' 2 8 14\n 4 10 16\n 6 12 18\n') self.assertEqual(str(self.c.transpose()), ' 1 0 0\n 0 1 0\n 0 0 1\n') self.assertEqual(str(self.a.transpose().transpose()), ' 1 2 3\n 4 5 6\n 7 8 9\n') self.assertEqual(str(self.e.transpose()), ' 0 0 0 1\n 0 0 1 0\n 0 1 0 0\n 1 0 0 0\n') > self.assertEqual(str(self.f.transpose()), ' 1 2 3 1\n 2 3 2 3\n 3 1 1 2\n') tests_matrix.py:34: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ self = 1 2 3 2 3 1 3 2 1 1 3 2 def transpose(self): nl…
4.13 LAB: JavaScript arrays Write the function divideArray() in script.js that has a single numbers parameter containing an array of integers. The function should divide numbers into two arrays, evenNums for even numbers and oddNums for odd numbers. Then the function should sort the two arrays and output the array values to the console. Ex: The function call: let nums = [4, 2, 9, 1, 8]; divideArray(nums); produces the console output: Even numbers: 2 4 8 Odd numbers: 1 9 The program should output "None" if no even numbers exist or no odd numbers exist. Ex: The function call: let nums = [4, 2, 8]; divideArray(nums); produces the console output: Even numbers: 2 4 8 Odd numbers: None Hints: Use the push() method to add numbers to the evenNums and oddNums arrays. Supply the array sort() method a comparison function for sorting numbers correctly. To test your code in your web browser, call divideArray() from the JavaScript console.