? What is the output of the following code #include using namespace std ; int main() { int i= 0, x = 0; do { if(i % 5== 0) { cout<
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- What is pass-by-value? What is pass-by-reference? Show the result of the following programs:a. Differentiate between implicit type conversiona nd Explicit type conversion with the help of example. b. What is the use of continue statement exaplin with appropriate example.Question 10 Write a program in Java that finds the Least common multiple of 2 numbers,please include comments and fully explain what the code does because I am not really understanding what loops are doing ! (I need a manual way to calculate the lcm and not use a function(method) or "findlcm"..!
- int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.In C++ what is the effect of the const keyword in the following statement? int* const intPtr = new intT/F 2. In Java, only if and if-else expressions are used in selection statements.
- Fix the following c++ code : #include<iostream>using namespace std;void Ashraf(int [][],int,int);int main(){int a[2][3];Ashraf(a,2,3);}void Ashraf (int a[ ] [], int R, int C){for(int r=0; r<R; r++){for(int c=0; c<C; c++){a[r][c]=1;cout<<a[r][c]<<"\t";}cout<<endl;}int main() { E(); C(); E(); } void B() {...} void C() {..} void D() {..} void E() { B(); D(); } A variable declared in function B and only in function B is accessible in?What is the output of the following C++ code? #include <iostream> using namespace std; class Base { public: int m; Base(int n=0) : m(n) { cout << "Base" << endl; } }; class Derived: public Base { public: double d; Derived(double de = 0.0) : d(de) { cout << "Derived" << endl; } }; int main() { cout << "Instantiating Base" << endl; Base cBase; cout << "Instantiating Derived" << endl; Derived cDerived; return 0; }
- Question 1 is already done need help with the others though This is the C code I have so far #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; struct employees **emps = new employees()[10]; //Added new statement ---- bartleby // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for(int i =0; i <9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to…Explain the steps in finding the output of the following code: #include <iostream>using namespace std; int main() { int arr[5] = {7, 2, 3, 6, 5}; int sum = 0; for (int i = 0; i < 5; ++i) { sum += arr[i]; } cout << " sum : " << sum << endl; return 0;}Here thr____Calculator.java, to accept an expression as astring in which the operands and operator are separated by zero or more spaces.For example, 3+4 and 3 + 4 are acceptable expressions. Here is a sample run:++