What is the rate law for the following mechanism: 2 A+B2C (fast equilibrium; rate of forward reaction: k1: rate of reverse reaction: k.1) B+C -D (slow, rate: k2) D -E (fast, rate: k3)

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section14.6: Reaction Mechanisms
Problem 2RC: A reaction is believed to occur by the following mechanism: Stepl: 2AI (Fast equilibrium) Step 2: I...
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What is the rate law for the following mechanism:
2 A+B2C (fast equilibrium; rate of forward reaction: k], rate of reverse reaction: k.1)
B+C -D (slow, rate: k2)
D - E
(fast, rate: k3)
Rate= k2 (k1/k.1) [A]²[B}²
OA.
O B. Rate= (k1 k1) [A][B]²
В.
Rate= k2 [B][C]
O D. Rate= k2 (k1/k1)[A]{{B]
O E. Rate= k2 [A]²B]²
Е.
Transcribed Image Text:What is the rate law for the following mechanism: 2 A+B2C (fast equilibrium; rate of forward reaction: k], rate of reverse reaction: k.1) B+C -D (slow, rate: k2) D - E (fast, rate: k3) Rate= k2 (k1/k.1) [A]²[B}² OA. O B. Rate= (k1 k1) [A][B]² В. Rate= k2 [B][C] O D. Rate= k2 (k1/k1)[A]{{B] O E. Rate= k2 [A]²B]² Е.
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