What is the rate law for the following mechanism: 2A +B + C →D (slow, rate: kj) A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2) E +G → H (fast, rate: k3)

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section14.6: Reaction Mechanisms
Problem 2RC: A reaction is believed to occur by the following mechanism: Stepl: 2AI (Fast equilibrium) Step 2: I...
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What is the rate law for the following mechanism:
2A +B + C →D (slow, rate: kj)
A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2)
E +G → H
(fast, rate: k3)
Rate= k1 [A]?[B][C]
O A.
Rate= k1 (k2/k.2)[A][D]
O B.
Rate= k1 [A][D]
OC.
Rate= kl (k2/k_2) [A][B][C]
O E. Rate= k1 (k2/k_2) [A]²[B][C]
Transcribed Image Text:What is the rate law for the following mechanism: 2A +B + C →D (slow, rate: kj) A+D 2E (fast equilibrium; rate of forward reaction: k2, rate of reverse reaction: k_2) E +G → H (fast, rate: k3) Rate= k1 [A]?[B][C] O A. Rate= k1 (k2/k.2)[A][D] O B. Rate= k1 [A][D] OC. Rate= kl (k2/k_2) [A][B][C] O E. Rate= k1 (k2/k_2) [A]²[B][C]
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