What is the theoretical yield of HCI if 30.0 g of BCI3 and excess H20 are reacted according to the following balanced reaction? BC13(g) +3 H20(1) → H3BO3(s) + 3 HCI(g) The following molar masses are: HCI = 36.46 g/mol BCI3 = 117.17 g/mol H20 = 18.02 g/mol 75.9 g HCI 132 g HCI 187 g HCI 56.0 g HCI 28.0 g HCI
What is the theoretical yield of HCI if 30.0 g of BCI3 and excess H20 are reacted according to the following balanced reaction? BC13(g) +3 H20(1) → H3BO3(s) + 3 HCI(g) The following molar masses are: HCI = 36.46 g/mol BCI3 = 117.17 g/mol H20 = 18.02 g/mol 75.9 g HCI 132 g HCI 187 g HCI 56.0 g HCI 28.0 g HCI
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.62P: 4-62 Iron ore is converted to iron by heating it with coal (carbon), and oxygen according to the...
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