What is the theoretical yield of HCI if 30.0 g of BCI3 and excess H20 are reacted according to the following balanced reaction? BC13(g) +3 H20(1) → H3BO3(s) + 3 HCI(g) The following molar masses are: HCI = 36.46 g/mol BCI3 = 117.17 g/mol H20 = 18.02 g/mol 75.9 g HCI 132 g HCI 187 g HCI 56.0 g HCI 28.0 g HCI

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What is the theoretical yield of HCI if 30.0 g of BCI3 and excess H20 are reacted
according to the following balanced reaction?
BC13(g) +3 H20(1)
H3BO3(s) + 3 HCI(g)
The following molar masses are:
HCI = 36.46 g/mol
BCI3 = 117.17 g/mol
%3D
H20 = 18.02 g/mol
75.9 g HCI
132 g HCI
187 g HCI
56.0 g HCI
28.0 g HCI
Transcribed Image Text:What is the theoretical yield of HCI if 30.0 g of BCI3 and excess H20 are reacted according to the following balanced reaction? BC13(g) +3 H20(1) H3BO3(s) + 3 HCI(g) The following molar masses are: HCI = 36.46 g/mol BCI3 = 117.17 g/mol %3D H20 = 18.02 g/mol 75.9 g HCI 132 g HCI 187 g HCI 56.0 g HCI 28.0 g HCI
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