The formation of ethyl alcohol (C2H5OH) by the fermentation of glucose (C,H12O6) may be represented by: CH12O6 → 2C2H$OH + 2CO2 If the percentage yield of a particular glucose fermentation process is 87.0%, how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol? [Molar mass: glucose = 180.0 g mol·' ; ethyl alcohol = 46.0 g mol"'] А. 68.3 В. 75.1 С. 115 D. 229 O A В D

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The formation of ethyl alcohol (C2HsOH) by the fermentation of glucose (C6H12O6)
may be represented by:
C6H12O6
→ 2C2H$OH + 2CO2
If the percentage yield of a particular glucose fermentation process is 87.0%, how
many grams of glucose would be required for the production of 51.0 g of ethyl
alcohol?
[Molar mass: glucose = 180.0 g moll ; ethyl alcohol = 46.0 g mol·']
А. 68.3
В. 75.1
С. 115
D. 229
O A
D
B.
Transcribed Image Text:The formation of ethyl alcohol (C2HsOH) by the fermentation of glucose (C6H12O6) may be represented by: C6H12O6 → 2C2H$OH + 2CO2 If the percentage yield of a particular glucose fermentation process is 87.0%, how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol? [Molar mass: glucose = 180.0 g moll ; ethyl alcohol = 46.0 g mol·'] А. 68.3 В. 75.1 С. 115 D. 229 O A D B.
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