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What is the theoretical yield of the solid product when 45.7 mL of 0.545M lead (II) nitrate is mixed with 34.7 mL of 0.595 M sodium chloride.

What is the theoretical yield of the solid product when 45.7 mL of 0.545M lead (II) nitrate is mixed with 34.7 mL of 0.595 M sodium chloride.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter3: Equation, The Mole, And Chemical Formulas
Section: Chapter Questions
Problem 3.133QE
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What is the theoretical yield of the solid product when 45.7 mL of 0.545M lead (II) nitrate is mixed with 34.7 mL of 0.595 M sodium chloride.

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Introduction

Chemically balanced equation for this reaction is,
2 NaCl (aq)  +  Pb(NO3)2 (aq) → PbCl2 (s)  +  2 NaNO3 (aq) 

Theoretical yield is the amount of product formed when the limiting reactant is consumed completely during the reaction. 

Limiting reactant is the reactant with less number of moles. 

Calculate number of moles of each reactant and then decide the limiting reactant. 

Given that,
 volume of Pb(NO3)2 = 45.7 mL = 0.0457 L
 concentration of Pb(NO3)2 = 0.545 M = 0.545 mol/L 
volume of NaCl = 34.7 mL = 0.0347 L 
concentration of NaCl = 0.595 M = 0.595 mol/L 



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