# What is the vapor pressure of a 49.9 percent C6H12O6 aqeous solution where the vapor pressure of the water is 375.0 mmHg at the given temperature.

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What is the vapor pressure of a 49.9 percent C6H12O6 aqeous solution where the vapor pressure of the water is 375.0 mmHg at the given temperature.

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Step 1

According to the statement of the question, 49.9 percent Glucose aqueous solution means that in 100 g of water 49.9 g of Glucose is present.

According to Raoult’s law mole fraction of a solute is equal to the relative vapor pressure lowering. It can be written as follows:

Here,

P0 is the vapor pressure of the solvent (pure water) that is given as 375.0 mmHg

P is the vapor pressure of the solution

X is the mole fraction of the Glucose

Step 2

The mole fraction of the glucose can be calculated by using the formula given below:

Here,

n is the number of moles of Glucose and N is the number of moles of water

Step 3

Number of moles of Glucose can be calculate...

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