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Asked Oct 20, 2019
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What is the volume of 0.7558 M HCl must be used with excess Fe to produce 1.732g of hydrogen? 2 Fe+8HCL to the product 2HeFeCl4+3H2.

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Expert Answer

Step 1

Given,

Molarity of HCl is 0.7558,

...

2 Fe (s)8HC1 (aq) 2 HFeC1 (aq)+ 3H2(g)
Two moles of iron react with eight moles of hydrochloric acid gives three moles of hydrogen
Number of moles of hydrogen is calculated as follows
Molar mass of hydrogen 2.015 g/mol
Mass
Moles
Molar mass
1.732g
Moles
2.015
Moles 0.860
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2 Fe (s)8HC1 (aq) 2 HFeC1 (aq)+ 3H2(g) Two moles of iron react with eight moles of hydrochloric acid gives three moles of hydrogen Number of moles of hydrogen is calculated as follows Molar mass of hydrogen 2.015 g/mol Mass Moles Molar mass 1.732g Moles 2.015 Moles 0.860

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