Question
Asked Oct 28, 2019

What mass of Ca(OH) is required to neutralize 50.00 mL of 0.180 M HCI?

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Step 1

Given information:

Volume of HCl = 50.00 mL

Concentration of HCl = 0.180 M

Step 2

Molarity is defined as the number of moles of solute dissolved in 1 L of solution and is denoted by M.

Thus, the number of moles of HCl solution can be calculated as follows:

n MxV
1L
0.180mol.Lx50.00 mLx-
1000mL
=0.009mol
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n MxV 1L 0.180mol.Lx50.00 mLx- 1000mL =0.009mol

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Step 3

The reaction of hydrochloric acid with calciu...

2HC1+СCа(ОН), >СаCl, + 2H,о
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2HC1+СCа(ОН), >СаCl, + 2H,о

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