What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 40.0 mL of 0.500 M NaOH in the following chemical reaction? Cu(NO₃)₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaNO₃(aq) According to the balanced reaction below, calculate the moles of NH₃ that form when 4.2 mol of N₂H₄ completely reacts 3N₂H₄(l) → 4NH₃(g) + N₂(g)   Consider the Haber-Bosch process for the synthesis of ammonia from its elements. Calculate the theoretical yield in moles NH₃ from the complete reaction of 15.6 grams H₂ in the presence of excess N₂ gas according to the following balanced chemical equation: N₂(g) + 3H₂(g) → 2NH₃(g)

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.120QE
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What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 40.0 mL of 0.500 M NaOH in the following chemical reaction? Cu(NO₃)₂(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + 2 NaNO₃(aq)

According to the balanced reaction below, calculate the moles of NH₃ that form when 4.2 mol of N₂H₄ completely reacts 3N₂H₄(l) 4NH₃(g) + N₂(g)
 
Consider the Haber-Bosch process for the synthesis of ammonia from its elements. Calculate the theoretical yield in moles NH₃ from the complete reaction of 15.6 grams H₂ in the presence of excess N₂ gas according to the following balanced chemical equation: N₂(g) + 3H₂(g) → 2NH₃(g)
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